C++一道题目，求解答。

Question

问题是这样的：
两个人玩捡树枝游戏，树枝的数量由用户来输入。但是树枝的数量不能超过21，用投掷硬币来决定先后顺序。每个人能一次性拿一枝或者两枝。谁拿到最后一枝树枝谁就输。
请用C++写出来。

Answer 1

 #include <time.h>
#include <iostream>
using namespace std;
int main()
{
    char player[2][40];
    int num,loop,loops,branch,start,branchTotal;
    int winCount[2]={0,0};

    cout<<"-------------树枝游戏---------------\n";
    cout<<"请输入第一名玩家姓名：";
    cin>>player[0];
    cout<<"请输入第二名玩家姓名：";
    cin>>player[1];

    do 
    {
        cout<<"请输入局数（不超过5局）：";
        cin>>loop;
    } while (loop>5 || loop<1);

    do 
    {
        cout<<"请输入每局树枝总数(不超过21枝)";
        cin>>branchTotal;
    } while (branchTotal>21 || branchTotal<1);

    loops=1;
    while(loops<=loop)
    {
        srand( (unsigned)time( NULL ) ); //根据时间生成随机数种子
        start = rand()%2;//随机产生谁先开始

        cout<<"\n\n<游戏第"<<loops<<"局开始，每次只能拿走1-2个树枝>\n";
        branch=branchTotal;
        while(branch>0)
        {
            cout<<"当前树枝总数:"<<branch<<"  ";
            do 
            {
                cout<<"请"<<player[start]<<"取树枝:";
                cin>>num;
            } while ( num<1 || num>2 );
            branch-=num;

            if(branch<=0)
            {
                cout<<player[start]<<"本局获胜！\n";
                winCount[start]++;
                break;
            }
            start=(start+1)%2;
        }

        loops++;
    }
    cout<<"--------游戏结束-----------\n";
    cout<<loop<<"局，"<<player[0]<<"胜"<<winCount[0]<<"局; "<<player[1]<<"胜"<<winCount[1]<<"局\n\n";
    if( winCount[0] > winCount[1]) 
    {
        cout<<"恭喜！最终"<<player[0]<<"获胜！\n";
    }
    else if( winCount[0] < winCount[1]) 
    {
        cout<<"恭喜！最终"<<player[1]<<"获胜！\n";
    }else
    {
        cout<<"平局！\n";
    }

    return 0;
}