 以特定格式输出两个数的和

Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32bit integer. You may assume the length of each integer will not exceed 1000.output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.Sample Input
2
1 2
112233445566778899 998877665544332211Sample Output
Case 1:
1 + 2 = 3Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110
//一看就是ACM题，贴上AC代码
#include<stdio.h>
#include<string.h>
int main()
{
char a[1000],b[1000],c[1001];
int i,j=1,p=0,n,n1,n2;
scanf("%d",&n);
while(n)
{
scanf("%s %s",a,b);
printf("Case %d:\n",j);
printf("%s + %s = ",a,b);
n1=strlen(a)1;
n2=strlen(b)1;
for(i=0;n1>=0n2>=0;i++,n1,n2)
{
if(n1>=0&&n2>=0){c[i]=a[n1]+b[n2]'0'+p;}
if(n1>=0&&n2<0){c[i]=a[n1]+p;}
if(n1<0&&n2>=0){c[i]=b[n2]+p;}
p=0;
if(c[i]>'9'){c[i]=c[i]10;p=1;}
}
if(p==1) printf("%d",p);
while(i)
printf("%c",c[i]);
j++;
if(n!=1) printf("\n\n");
else printf("\n");
}
}
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20161109#include<stdio.h> #include<ctype.h> #include<stdbool.h> #define STOP '' int main(void) { char c; char prev; long n_chars = 0L; int n_lines = 0; int n_words = 0; int p_lines = 0; bool inword = false; printf("enter next to be analyzed ( to terminate):\n"); prev = '\n'; while ((c = getchar()) != STOP) { n_chars++; if (c == '\n') n_lines++; if (!isspace(c) && !inword) { inword = true; n_words++; } if (isspace(c) && inword) inword = false; prev = c; } if (prev != '\n') p_lines = 1; printf("characters=%ld,words=%d,lines=%d,", n_chars, n_words, n_lines); printf("partial lines=%d\n", p_lines); getchar(); getchar(); return 0; } 第二个if那里，！inword为假，那为什么要把 bool inword声明为false？我觉得把inword声明为true更方便呀，intword声明为false，然后！inword也是false，这样或许会让人产生理解错误？
为什么在 c + + 中读取 stdin 行比读取 Python 慢得多？_course
20120221<div class="posttext" itemprop="text"> <p>I wanted to compare reading lines of string input from stdin using Python and C++ and was shocked to see my C++ code run an order of magnitude slower than the equivalent Python code. Since my C++ is rusty and I'm not yet an expert Pythonista, please tell me if I'm doing something wrong or if I'm misunderstanding something.</p> <hr> <p>(TLDR answer: include the statement: <code>cin.sync_with_stdio(false)</code> or just use <code>fgets</code> instead.</p> <p>TLDR results: scroll all the way down to the bottom of my question and look at the table.)</p> <hr> <p><strong>C++ code:</strong></p> <pre><code>#include <iostream> #include <time.h> using namespace std; int main() { string input_line; long line_count = 0; time_t start = time(NULL); int sec; int lps; while (cin) { getline(cin, input_line); if (!cin.eof()) line_count++; }; sec = (int) time(NULL)  start; cerr << "Read " << line_count << " lines in " << sec << " seconds."; if (sec > 0) { lps = line_count / sec; cerr << " LPS: " << lps << endl; } else cerr << endl; return 0; } // Compiled with: // g++ O3 o readline_test_cpp foo.cpp </code></pre> <p><strong>Python Equivalent:</strong></p> <pre><code>#!/usr/bin/env python import time import sys count = 0 start = time.time() for line in sys.stdin: count += 1 delta_sec = int(time.time()  start_time) if delta_sec >= 0: lines_per_sec = int(round(count/delta_sec)) print("Read {0} lines in {1} seconds. LPS: {2}".format(count, delta_sec, lines_per_sec)) </code></pre> <p><strong>Here are my results:</strong></p> <pre><code>$ cat test_lines  ./readline_test_cpp Read 5570000 lines in 9 seconds. LPS: 618889 $cat test_lines  ./readline_test.py Read 5570000 lines in 1 seconds. LPS: 5570000 </code></pre> <p><em>I should note that I tried this both under Mac OS X v10.6.8 (Snow Leopard) and Linux 2.6.32 (Red Hat Linux 6.2). The former is a MacBook Pro, and the latter is a very beefy server, not that this is too pertinent.</em></p> <pre><code>$ for i in {1..5}; do echo "Test run $i at `date`"; echo n "CPP:"; cat test_lines  ./readline_test_cpp ; echo n "Python:"; cat test_lines  ./readline_test.py ; done Test run 1 at Mon Feb 20 21:29:28 EST 2012 CPP: Read 5570001 lines in 9 seconds. LPS: 618889 Python:Read 5570000 lines in 1 seconds. LPS: 5570000 Test run 2 at Mon Feb 20 21:29:39 EST 2012 CPP: Read 5570001 lines in 9 seconds. LPS: 618889 Python:Read 5570000 lines in 1 seconds. LPS: 5570000 Test run 3 at Mon Feb 20 21:29:50 EST 2012 CPP: Read 5570001 lines in 9 seconds. LPS: 618889 Python:Read 5570000 lines in 1 seconds. LPS: 5570000 Test run 4 at Mon Feb 20 21:30:01 EST 2012 CPP: Read 5570001 lines in 9 seconds. LPS: 618889 Python:Read 5570000 lines in 1 seconds. LPS: 5570000 Test run 5 at Mon Feb 20 21:30:11 EST 2012 CPP: Read 5570001 lines in 10 seconds. LPS: 557000 Python:Read 5570000 lines in 1 seconds. LPS: 5570000 </code></pre> <hr> <p>Tiny benchmark addendum and recap</p> <p>For completeness, I thought I'd update the read speed for the same file on the same box with the original (synced) C++ code. Again, this is for a 100M line file on a fast disk. Here's the comparison, with several solutions/approaches:</p> <pre><code>Implementation Lines per second python (default) 3,571,428 cin (default/naive) 819,672 cin (no sync) 12,500,000 fgets 14,285,714 wc (not fair comparison) 54,644,808 </code></pre> </div> <p>转载于:https://stackoverflow.com/questions/9371238/whyisreadinglinesfromstdinmuchslowerincthanpython</p>
21天通关Python（仅视频课）
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navicat简体中文版 绿色版 （64位）
20160923解压后安装navicat，打开navicat执行PatchNavicat即破解成功。可以正常使用啦。
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