create table user
(
id int primary key aotu_increment,
name varchar(40),
password varchar(40),
email varchar(40),
birthday date
)character set utf8 collate utf8_general_ci;
insert into user(name,password,eamil,birthday) values('zs','123456','zs@sina.com','1980-12-04');
insert into user(name,password,eamil,birthday) values('lisi','123456','lisi@sina.com','1981-12-04');
insert into user(name,password,eamil,birthday) values('wangwu','123456','wangwu@sina.com','1979-12-04');

求解 mysql数据库第三行错误 birthday
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4条回答 默认 最新
- Yiran8935 2016-01-29 03:41关注
create table
user
(id
int primary key AUTO_INCREMENT,name
varchar(40),password
varchar(40),email
varchar(40),birthday
date
)character set utf8 collate utf8_general_ci;insert into
user
(name
,password
,email
,birthday
) values('zs','123456','zs@sina.com','1980-12-04');
email 不是eamil
而且mySql里面用的都是二楼说的1左边的那个符号本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报