任意输入两个字符串(如"Jiangsu China"和"hello!")
并存放在a、b两个数组中。把较短的字符串放在a数组,
较长的字符串放在b数组,并输出。#include
using namespace std;
void swap(char a[], char b[], int n) {
char ch; char k=0;
for (int k = 0; k < n; k++)
ch = a[k]; a[k] = b[k]; b[k] = ch;
}
int main(void)
{
char a[100], b[100];
cin >> a >> b;
cout << "a=" << a << ",b=" << b << '\n';
int c = strlen(a), d = strlen(b);
if (c > d) swap(a, b, d);
cout << "a=" << a << ",b=" << b << '\n';
C++小程序,调试,在我这个基础上调试
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threenewbee 2016-02-20 16:17关注#include<iostream> using namespace std; void swap(char a[], char b[], int n, int m) { char ch; int k; for (k = 0; k < m; k++) //这里少括号,并且复制不全 { ch = a[k]; a[k] = b[k]; b[k] = ch; } b[m] = '\0'; } int main(void) { char a[100], b[100]; cin >> a >> b; cout << "a=" << a << ",b=" << b << '\n'; int c = strlen(a), d = strlen(b); if (c > d) swap(a, b, d, c); cout << "a=" << a << ",b=" << b << '\n'; return 0; }解决 无用评论 打赏 举报