Java语言程序设计第4章编程练习题1求问

Question

import java.util.Scanner;

public class Practice {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        int data = 0;
        int positive = 0;
        int negative = 0;
        int sum = 0;
        int count = 0;
        System.out.print("Enter int value (0 for exit):");

        do {
            data = input.nextInt();
            if (data > 0)
                positive += 1;
            else 
                negative += 1;
            sum += data;
            count += 1;
        }while (input.hasNextInt() && data != 0);

        double average = sum / count;
        System.out.println("The totla is " + sum);
        System.out.println("The average is " + average);
    }
}

执行的时候不显示结果，0退出不了。怎样能够达到输出这样的结果啊？

• Enter int value(0 for exit):
• 1 2 -1 3 0 (enter)
• The number of positives is 3
• The number of positives is 1
• The number of positives is 1The total is 5
• The average is 1.25

Answer 1

将while循环里面的条件交换一下位置就行了
while(data!=0 && input.hasNextInt())