mem_fox 2016-02-29 16:48 采纳率: 0%
浏览 1462

怎么能把这段Ruby代码改的更像Ruby的

def match_standard?()
standard = StandardBodyGrith.find_by_leight_and_sex(1700,'M')
print standard
print shoulder
is_match = Array.new(6)
is_match[0] = shoulder < standard.shoulder
is_match[1] = chest < standard.chest
is_match[2] = arm_relaxed < standard.arm_relaxed
is_match[3] = waist < standard.waist
is_match[4] = hip < standard.hip
is_match[5] = thigh < standard.thigh
return is_match
end

2个对象的shoulder/chest/arm relaxed/waist/hip/thigh 6个属性是一一对应的,我怎么比较直接生成一个boolean的数组?

  • 写回答

3条回答 默认 最新

  • devmiao 2016-03-08 05:01
    关注

    可以用hashtable

    评论

报告相同问题?