离散数学,,,求大神解答

求 (¬p∨¬q)→(p↔¬q)的主析取范式和主合取范式
求解答求解答求解答求解答求解答求解答

3个回答

什么情况啦啦啦啦啦聊了聊图片

额,离散中这个是基本的好吧,慢慢学哦

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为什么我下android studio里java中没有src,也没有gen文件?会对我的编程有影响吗?![图片](https://img-ask.csdn.net/upload/201611/13/1478967421_859164.jpg)
求大神解答而已
[img=https://img-bbs.csdn.net/upload/201504/15/1429109837_984843.jpg][/img]rnrn这是我们学校Linux兴趣小组的官网首页rn因为快纳新了 所以先出一个 免试题来rn先看这个免试题吧 一开始我也很疑惑 不知道干什么 昨天听一个同学说了说rn这是主页 然后不论点下面的哪个选项 都是一直显示主页rn应该这就是问题吧 如何破解还是什么?rn我也不知道 我只是起步的菜鸟rn但是我也想进实验室 想掌握更好的技术rn所以 有没有大神告诉我 rn这是什么原理或者主要想搞什么rn谢谢
求大神解答查错
#includern#includern#includernusing namespace std;rnstruct flight //航班信息rnrn char a1[10]; //航班号rn string a2; //起飞时间rn string a3; //降落时间rn char a4[10]; //起飞城市rn char a5[10]; //降落城市rn int a6; //价格rn int a7; //票价折扣 rn int a8; //余票rnfl[10];rnstruct customer //客户信息rnrn char name[10]; //定义字符型数组姓名name[10]rn int seat; //定义整型变量座位号seatrn char num[10]; //定义字符型数组航班号num[10]rn char no[18]; //证件号norn int ps; //订票数psrn string qfs; //起飞时间qfsrn string jls; //降落时间jlsrn char qfd[10]; //起飞城市qfdrn char jld[10]; //降落城市jldrn int pj; //票价pjrncu[200];rnint cnum=3;rnint len=0;rnint A=0;rnvoid luru(); //声明录入函数rnvoid chaxun(); //声明查询函数rnvoid chaxun1(); //声明查询方式1函数rnvoid chaxun2(); //声明按查询方式2函数rnvoid dingpiao(); //声明订票函数rnvoid tuipiao(); //声明退票函数rnvoid xiugai(); //声明修改函数rnvoid menu(); //声明主菜单函数rnvoid duqu(); //声明文件读取函数rnvoid tuichu(); //声明退出并保存函数rnrnrnvoid luru() //航班信息录入rn rn cout<<"请输入航班信息:"<>fl[len].a1; //录入航班号rn cout<<"起飞时间"<>fl[len].a2; //录入起飞时间rn cout<<"降落时间"<>fl[len].a3; //录入降落时间rn cout<<"起飞城市"<>fl[len].a4; //录入起飞城市rn cout<<"降落城市"<>fl[len].a5; //录入降落城市rn cout<<"票价"<>fl[len].a6; //录入票价rn cout<<"折扣"<>fl[len].a7; //录入机票折扣rn cout<<"剩余票量"<>fl[len].a8; //录入剩余票量rn len++;rn cout<<"请选择所要进行的操作"<>t; //选择查询方式rn switch(t)rn rn case 1:rn chaxun1();rn break;rn case 2:rn chaxun2();rn break;rn default:cout<<"输入的数据有误,请重新输入!"<>n;rn for(int j=0;j>m1>>m2; //输入起始城市和降落城市rn for(j=0;j>Name; //输入乘客姓名rn cin>>fn; //输入乘客所要订的航班号rn for(int i=0;i0) rn strcpy(cu[A].name,Name);rn strcpy(cu[A].num,fn);rn cu[A].seat=fl[i].a8;rn A++;fl[i].a8--;sign=1;rn cout<<"订票成功!"<>Name; //输入乘客姓名rnrn cout<<"请输入航班号:";cin>>fn;cout<>num;int z=0;int j;rn for(int z=0;z>fl[j].a2;cout<<"达到时间:";cin>>fl[j].a3;cout<(&cu[i])),sizeof(customer));cout<<"写入成功!"<(&fl[i])),sizeof(flight));//将航班信息写入文件rn infile1.close(); //关闭文件rnrnrnvoid duqu() //读取文件信息rn rn ifstream infile1("airline.dat",ios_base::binary); rn while(infile1.peek()!=EOF) rn rn infile1.read((reinterpret_cast(&fl[len])),sizeof(flight));//输入方式读取文件rn cout<<"***航班信息****"<(&cu[A++])),sizeof(customer)); //输入方式读取文件rn infile2.close(); //关闭文件rn getchar();system("cls");rnrnvoid menu()rnrn cout<<"*******************航班订票系统*********************"<>i; //选择菜单rn switch(i)rn rn case 1:rn luru(); rn break;rn case 2:rn chaxun(); rn break;rn case 3:rn dingpiao();menu();rn case 4:rn tuipiao();rn menu();rn case 5:rn xiugai();rn menu();rn case 6:rn tuichu();rn exit(1); //退出rn break;rn default:cout<<"输入的选项不合法,请重新输入"<
求大神帮忙解答!
[img=https://img-bbs.csdn.net/upload/201607/09/1468029033_463634.png][/img]rn这种效果怎么做rn[img=https://img-bbs.csdn.net/upload/201607/09/1468029164_749260.png][/img]rn一部分是这个
求大神解答~
public static String tostring(int[] arr)rn if (arr==null) rn return null;rn rn if (arr.length==0) rn return "[]";rn rn StringBuilder sb=new StringBuilder();rn sb.append("[");rn for (int i = 0;i
新人求大神解答
html的代码是 rnjs代码是 alert($('#xztab').value);rn为什么输出是 undefined!rn大神路过求解答
初学者,求大神解答
为什么这两代码在控制台那里运行不出来,显示的是我之前打的同一包中不同类的运行结果,求解答,,rn[img=https://img-bbs.csdn.net/upload/201907/30/1564453771_99934.png][/img][img=https://img-bbs.csdn.net/upload/201907/30/1564453776_146129.png][/img]
大神求解答
在存储过程创建的DW中,rn存储过程:execute dbo.sp_whs_user_define_item_activity;1 @as_col_list='(cust_code)[cust_code] (cust_name)[cust_name] (warehouse_name)[whs_name] (gdw_no)[gdw_no] (gdw_uid)[gdw_uid] (gdw_delivery_by)[delivery_by] (receive_date)[recv_date] (receive_date_time)[recv_time] (gdw_vehicle_no)[car_no] (vessel_name)[vsl_name] (pkg_unit_desc)[pkg_unit_desc] (voyage)[voy_no] (gdw_cntr_no)[cntr_no] (gdw_seal_no)[seal_no] (gdw_cntr_size)[cntr_size] (gdw_load_code)[load_code] (gdw_dish_code)[dish_port] (job_no)[job_no] (gdw_hawb_hbl_no)[hbl_no] (gdw_mawb_mbl_no)[cbl_no] (eta)[eta] (gdw_issue_date)[issue_date] (lot_no)[lot_no] (gdw_remark)[gdw_remark] (etd)[etd] (cust_addr01)[cu_addr_01] (cust_addr02)[cu_addr_02] (cust_addr03)[cu_addr_03] (cust_addr04)[cu_addr_04] (cust_addr05)[cu_addr_05] (lot_no)[lot_no] (client_item_no)[client_item_no] (gdwlot_client_lot_no)[client_lot_no] (booked_pkg)[pkg] (pkg_unit)[pkg_unit] (booked_inpkg)[in_pkg] (in_pkg_unit)[in_pkg_unit] (booked_cbm)[cbm] (booked_kgs)[kgs] (width)[width] (whs_loc)[loc_code] (gdwlot_remark)[gdwlot_remark] (description)[descp] (marks)[marks] (height)[height] (item_no)[maitem_item_no] (length)[lenght]',@as_active_type='I',@as_with_sub_table='0000',@as_date_fm='1900-1-1',@as_date_to='2099-12-31',@as_pgdw_where = ' and 1=2',@as_pdo_where = ' and 1=2',@as_do_where = ' and 1=2',@as_display_doctype='0100',@as_pb_prt_arg='''901508000171'',''90F10000023''' rn能运行rn在PB中添加存储过程代码rnexecute dbo.sp_whs_user_define_item_activity;1 @as_col_list='(cust_code)[cust_code] (cust_name)[cust_name] (warehouse_name)[whs_name] (gdw_no)[gdw_no] (gdw_uid)[gdw_uid] (gdw_delivery_by)[delivery_by] (receive_date)[recv_date] (receive_date_time)[recv_time] (gdw_vehicle_no)[car_no] (vessel_name)[vsl_name] (pkg_unit_desc)[pkg_unit_desc] (voyage)[voy_no] (gdw_cntr_no)[cntr_no] (gdw_seal_no)[seal_no] (gdw_cntr_size)[cntr_size] (gdw_load_code)[load_code] (gdw_dish_code)[dish_port] (job_no)[job_no] (gdw_hawb_hbl_no)[hbl_no] (gdw_mawb_mbl_no)[cbl_no] (eta)[eta] (gdw_issue_date)[issue_date] (lot_no)[lot_no] (gdw_remark)[gdw_remark] (etd)[etd] (cust_addr01)[cu_addr_01] (cust_addr02)[cu_addr_02] (cust_addr03)[cu_addr_03] (cust_addr04)[cu_addr_04] (cust_addr05)[cu_addr_05] (lot_no)[lot_no] (client_item_no)[client_item_no] (gdwlot_client_lot_no)[client_lot_no] (booked_pkg)[pkg] (pkg_unit)[pkg_unit] (booked_inpkg)[in_pkg] (in_pkg_unit)[in_pkg_unit] (booked_cbm)[cbm] (booked_kgs)[kgs] (width)[width] (whs_loc)[loc_code] (gdwlot_remark)[gdwlot_remark] (description)[descp] (marks)[marks] (height)[height] (item_no)[maitem_item_no] (length)[lenght]',@as_active_type='I',@as_with_sub_table='0000',@as_date_fm='1900-1-1',@as_date_to='2099-12-31',@as_pgdw_where = ' and 1=2',@as_pdo_where = ' and 1=2',@as_do_where = ' and 1=2',@as_display_doctype='0100',@as_pb_prt_arg=:as_uid_listrn添加参数值就会提示rnselect Error: failed to put data to safearrayrn错误rn确信就是这里出了问题,求解
求大神帮忙解答~~~
大神们 帮我看下,为什么int类型超出最大值范围,输出最后会变成0, 而不是负数?[img=https://img-bbs.csdn.net/upload/201312/07/1386418079_613433.jpg][/img]
各位大神求解答
本人刚学软件的菜鸟,利用不安全代码unsafe使用指针对图像进行雾化,但是有的图像可以运行,rn有的老是出现下面的警告:rnrn“System.AccessViolationException”类型的未经处理的异常出现在 雾化效果.exe 中。rnrn其他信息: 尝试读取或写入受保护的内存。这通常指示其他内存已损坏。rnrnrn本人的源程序如下:rnusing System;rnusing System.Collections.Generic;rnusing System.ComponentModel;rnusing System.Data;rnusing System.Drawing;rnusing System.Linq;rnusing System.Text;rnusing System.Windows.Forms;rnusing System.Drawing.Imaging;rnrnnamespace 雾化效果rnrn public partial class Form1 : Formrn rn public Form1()rn rn InitializeComponent();rn rn Bitmap bmp;rn private void button1_Click(object sender, EventArgs e)rn rn OpenFileDialog ofd = new OpenFileDialog();rn ofd.Filter = "JEPG文件(*.jpg)|*.jpg";rn ofd.ShowDialog();rn if (ofd.FileName != "")rn rn pictureBox1.Visible = true;rn bmp = new Bitmap(ofd.FileName);rn pictureBox1.Image = bmp;rn pictureBox1.SizeMode = PictureBoxSizeMode.StretchImage;rn rn elsern return;rn rnrn private void button2_Click(object sender, EventArgs e)rn rn Bitmap b = (Bitmap)bmp.Clone();rn BitmapData bmData = b.LockBits(new Rectangle(0,0,b.Width,b.Height)rn ,ImageLockMode.ReadWrite,PixelFormat.Format24bppRgb);rn int stride = bmData.Stride;rn System.IntPtr Scan0=bmData.Scan0;rn unsafern rn byte* p=(byte*)(void*)Scan0;rn int Offset=stride-3*b.Width;rn int red, green, blue;rn for (int j = 0; j < b.Height; ++j)rn rn for (int i = 0; i < b.Width; ++i)rn rn Random R = new Random();rn int r = R.Next(200000);rn int x = j + r % 8;rn int y = i + r % 8;rn if (x >= b.Width) x = b.Width - 1;rn if (y >= b.Height) y = b.Height - 1;rn red = (p +( 3 * (y-i) + (x-j) * (3 * (b.Width-1) + Offset)))[0];rn green = (p + (3 * (y-i) + (x-j) * (3 * (b.Width-1) + Offset)))[1];rn blue = (p + (3 * (y-i) + (x-j) * (3 * (b.Width-1) + Offset)))[2];rn p[0] = (byte)red;rn p[1] = (byte)green;rn p[2] = (byte)blue;rn p += 3;rn rn p += Offset;rn rn b.UnlockBits(bmData);rn pictureBox1.Image = b;rn rnrn rn rnrn求大神指导啊,灰常感谢。[/size]
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