C++ CString字符串转换问题

Question

代码如下：
CString TxtPath;
CStdioFile File;
CString buffer;
UINT Num = 0u;
m_Script.GetWindowText(TxtPath);
File.Open(TxtPath,CFile::modeRead);
File.SeekToBegin();
while ( File.ReadString(buffer) )
{
}

如果读取的文件中存储的数据为： 9812345678
如何将文件中读取的内容，转换为UINT8格式的数据存储，也就是存储在 UINT8 Text[] 数组中，存储
后数组中的内容为：Text[] = {0x98,0x12,0x34,0x56,0x78}

无C币了，技术讨论，不胜感激！

Answer 1

 char * s=strtest.GetBuffer(strtest.GetLength());
byte * b= new byte[strlen(s) / 2];
for (int i = 0; i < strlen(s) / 2; i++)
{
if (s[i/2] >= 'a' && s[i/2] <= 'f') b[i] += 16 * (s[i/2] - 'a' + 10);
if (s[i/2] >= 'A' && s[i/2] <= 'F') b[i] += 16 * (s[i/2] - 'A' + 10);
if (s[i/2] >= '0' && s[i/2] <= '9') b[i] += 16 * (s[i/2] - '0');
if (s[i/2+1] >= 'a' && s[i/2+1] <= 'f') b[i] += (s[i/2+1] - 'a' + 10);
if (s[i/2+1] >= 'A' && s[i/2+1] <= 'F') b[i] +=(s[i/2+1] - 'A' + 10);
if (s[i/2+1] >= '0' && s[i/2+1] <= '9') b[i] +=* (s[i/2+1] - '0');
}