SELECT e.`ID`,e.`EmployeeID`,e.`CHNName`,e.`ENGName`,e.`Sex`,e.`Mobile`
FROM tb_pcm_coach c,tb_sys_employee e,tb_sys_employeetype tt, tb_sys_department d
WHERE c.ID=e.ID AND e.ID=tt.Employee AND e.dept = d.id
<!-- AND tt.EmployeeType='EB43871E-1E7C-48CB-B38D-9E3200D011F7}'-->
AND e.STATUS='FDCAAF7C-8FE8-4340-993E-9E29000B6F14'
<!--AND c.ID IN(SELECT coach FROM tb_mms_coachbuy) -->
<if test="employeetype != null and '' != employeetype">
and tt.EmployeeType= #{employeetype}
</if>
<if test="dept != null and '' != dept">
and INSTR(d.TreeKey, #{dept}) = 1
</if>
<if test="coachlevel != null and '' != coachlevel">
and c.CoachLevel= #{coachlevel}
</if>
<if test="eid != null and '' != eid">
and e.ID != #{eid}
</if>
<!-- Combobox精确查询 -->
<if test="CHNName != null and '' != CHNName">
and e.CHNName like '%#{CHNName}%'
</if>
</select>
最下面like我想查e.CHNName包括传入的CHNName,也就是like的值不固定,请问应该怎么写?
已解决,我从其他模块借鉴的
<if test="departmentname != null and '' != departmentname">
and INSTR(d.departmentname,#{departmentname}) > 0
</if>
mysql中有一个方法 INSTR可以比对两个字符串。