烦请各位大神给小妹瞅瞅

Question

#include
using namespace std;
class xx
{
public:
xx()
{
quantity=0;
price=0;
}
void total();
static float average();
static void display();
private:

int quantity;
float price;
static double discount;
static float sum;
static int n;

};
void xx:: total()
{

if(quantity>=10)
    price=0.98*price;
    sum=quantity*price;
n+=quantity;

}float xx::average()
{
return(sum/n);
}
double xx::discount=0.98;
float xx::sum=0;
int xx::n=0;
void xx::display()
{
cout<<"sum:"<<sum<<" "<<"average:"<<xx::average()<<endl;
}
int main()
{
xx t1[3]={xx(5,23.5),
xx(12,24.56),
xx(100,21.5),
}
t1[0].total ();

t1[1].total ();

t1[2].total ();

t1.display();
return 0;

}
问题；C:\Users\dell\Desktop\8.cpp(42) : error C2661: 'xx::xx' : no overloaded function takes 2 parameters

Answer 1

因为楼主下面xx(5,23.5)是这样创建对象的，但又没有重载的构造函数满足，所以会报错
在类xx里面定义一个这样的构造函数就行了
另外还有两个小地方要改一下，我都标注了

 #include<iostream>
#include<string>
using namespace std;
class xx
{
public:
    xx()
    {
        quantity=0;
        price=0;
    }
    xx(int a, float b) //第一处问题
    {
        quantity = a;
        price = b;
    }
    void total();
    static float average();
    static void display();
private:
    int quantity;
    float price;
    static double discount;
    static float sum;
    static int n;
};
void xx:: total()
{
    if(quantity>=10)
        price=0.98*price;
    sum=quantity*price;
    n+=quantity;
}float xx::average()
{
    return(sum/n);
}
double xx::discount=0.98;
float xx::sum=0;
int xx::n=0;
void xx::display()
{
    cout<<"sum:"<<sum<<" "<<"average:"<<xx::average()<<endl;
}
int main()
{
    xx t1[3]={xx(5,23.5),
        xx(12,24.56),
        xx(100,21.5),
    };             //第二处，少了分号
    t1[0].total ();
    t1[1].total ();

    t1[2].total ();

    t1[0].display(); //第三处
    return 0;
}