ajax异步上传(没有form表单);单纯的提交文件

Question

 <div class="input-group col-md-9 pull-left">
                   <input class="form-control" ng-file-select="onFileSelect($files)" enctype="multipart/form-data" accept=".txt,.csv" ng-disabled="uploading" type="file" name="userfile">
                    <span class="input-group-btn">
                        <button class="btn btn-primary" type="submit" onclick="upload(<?=!empty($info['id']) ? $info['id'] : ''?>)" ng-disabled="uploading" >上传</button>
                    </span>
                </div>

Answer 1

$.ajax({

         type: "GET",

         url: "test.json",

         data: {},//data中可以提交你想要提交过去的数据

         dataType: "json",

         success: function(data){
                  }
                        error : function(){
                                        alert("异步加载错误");
                                        }