我在开发一个程序,在 webpage 上使用jquery。
$.post(url, {param: paramstring}, function(result){});
根据参数结构,Paramstring 是一个 json字符串,如:{"action":"get","username":"username"}
现在我想在android中运行,再在页面上添加两个textview 来输入用户名和密码。也有一个注册按钮。按钮监听程序:
EditText et1 = (EditText)findViewById(R.id.username);
String user = et1.getText().toString();
EditText et2 = (EditText)findViewById(R.id.pass);
String password = et2.getText().toString();
// the password should upload after MD5 encryption. this is encryption method. the result is the same with js encryption.
String password_md5 = toMd5(password.getBytes());
Log.d(TAG, user+"-"+password+"-"+password_md5);
try {
HttpPost request = new HttpPost(URL);
JSONObject params = new JSONObject();
params.put("action", "get");
params.put("result", "user");
params.put("category", "base");
params.put("username", user);
params.put("password", password_md5);
List<BasicNameValuePair> sendData = new ArrayList<BasicNameValuePair>();
sendData.add(new BasicNameValuePair("param", params.toString()));
System.out.println(params.toString());
request.setEntity(new UrlEncodedFormEntity(sendData,"utf-8"));
System.out.println(EntityUtils.toString(request.getEntity()));
HttpResponse response= new DefaultHttpClient().execute(request);
String retSrc = EntityUtils.toString(response.getEntity());
System.out.println(retSrc);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
上面的代码返回数据显示登录错误,我觉得是因为 json 结构的问题。{param:paramstr} in $.post()
方法是一个map。我改了好几次还是错误的。
什么问题呢?