在java EE里面通过jfinal里面的插件C3p0来连接sqlserver数据库Test,然后
通过tomcat发布到网上,在android服务器端来接受数据,在界面上显示,但是这里出现了非常离奇的错误
在里面显示:" ` "这个附近有错误,但是我程序里面没有这个符号呀
主程序:
package jfinal;
import com.jfinal.config.Constants;
import com.jfinal.config.Handlers;
import com.jfinal.config.Interceptors;
import com.jfinal.config.JFinalConfig;
import com.jfinal.config.Plugins;
import com.jfinal.config.Routes;
import com.jfinal.plugin.activerecord.ActiveRecordPlugin;
import com.jfinal.plugin.c3p0.C3p0Plugin;
public class jfinalConfig extends JFinalConfig {
@Override
public void configConstant(Constants me) {
me.setDevMode(true);
}
@Override
public void configRoute(Routes me) {
me.add("/Test", indexController.class);
}
@Override
public void configPlugin(Plugins me) {
C3p0Plugin cp = new C3p0Plugin("jdbc:sqlserver://localhost:1433;DatabaseName=Test","sa","12345","com.microsoft.sqlserver.jdbc.SQLServerDriver");
me.add(cp);
ActiveRecordPlugin arp = new ActiveRecordPlugin(cp);
me.add(arp);
arp.addMapping("Test", Test.class);
}
@Override
public void configInterceptor(Interceptors me) {
}
@Override
public void configHandler(Handlers me) {
}
}
以及
package jfinal;
import com.jfinal.plugin.activerecord.Model;
public final class Test extends Model {
public static final Test dao = new Test();
}
还有
package jfinal;
import java.util.List;
import com.jfinal.core.Controller;
public class indexController extends Controller {
public void index(){
List list = Test.dao.find("select*from Test");
renderJson(list);
}
public void ask(){
renderText("ask");
}
}
错误居然回事这样
五月 05, 2016 12:22:53 下午 org.apache.catalina.core.StandardContext filterStart
严重: Exception starting filter jfinal
java.lang.RuntimeException: Plugin start error: com.jfinal.plugin.activerecord.ActiveRecordPlugin.
com.microsoft.sqlserver.jdbc.SQLServerException: '`' 附近有语法错误。
我在代码里面没有写这个" ` "这个符号呀,大家知道为什么会提示有这个错误吗