C++ STL的merge函数越界

Question

小白想问问大神，用merge函数时一直报错，说iterator越界
代码如下：
#include
#include
#include
#include
using namespace std;

void display(vector &v)
{
for (vector::iterator it = v.begin(); it != v.end();++it)
{
cout<<*it<<endl;
}
cout<<endl;
}

int main()
{
vector v1,v2,v3;
for (int i =0; i<=2 ;++i)
{
v1.push_back(i);
}
for (int i =3; i<=7 ;++i)
{
v2.push_back(i);
}
for (int i =8; i<=10 ;++i)
{
v3.push_back(i);
}
merge(v1.begin(),v1.end(),v2.begin(),v2.end(),v3.begin());
display(v3);
system("pause");
return 0;
}

谢谢大神

Answer 1

v3需要resize一下才行
PS：而且merge(v1.begin(),v1.end(),v2.begin(),v2.end(),v3.begin());这样用的话，v3前面的三个元素会被覆盖掉

 #include<iostream>
#include<vector>
#include<algorithm>  
using namespace std;
void display(vector<int> &v)
{
    for (vector<int>::iterator it = v.begin(); it != v.end();++it)
    {
        cout<<*it<<endl;
    }
    cout<<endl;
}
int main()
{
    vector<int> v1,v2,v3;
    for (int i =0; i<=2 ;++i)
    {
        v1.push_back(i);
    }
    for (int i =3; i<=7 ;++i)
    {
        v2.push_back(i);
    }
    for (int i =8; i<=10 ;++i)
    {
        v3.push_back(i);
    }
    v3.resize(11);
    merge(v1.begin(),v1.end(),v2.begin(),v2.end(),v3.begin());
    display(v3);
    system("pause");
    return 0;
}