离散数学实验用c++实现序偶转换为关系矩阵

Question

求离散数学c++代码，把一个序偶关系转换为关系矩阵，例如输入;;;;;会输出对应的关系矩阵

Answer 1

用C#写一个给你

 using System;
using System.Linq;

public class Test
{
    public static void Main()
    {
        // your code goes here
        string s = "<a,b>;<b,c>;<a,d>;<c,e>;<e,a>;<d,b>";
        int n = s.Where(x => x >= 'a' && x <= 'z').Max() - 'a' + 1;
        int[,] arr = new int[n, n];
        foreach (var item in s.Split(';').Select(x => new { a = x[1] - 'a', b = x[3] - 'a' }))
        {
            arr[item.a, item.b] = 1;
        }
        for (int i = 0; i < n; i++)
        {
            for (int j = 0; j < n; j++)
            {
                Console.Write(arr[i, j] + "\t");
            }
            Console.WriteLine();
        }
    }
}

0 1 0 1 0

0 0 1 0 0

0 0 0 0 1

0 1 0 0 0

1 0 0 0 0