html文档结构如下:
<body>
<div>
<a href="3" class="meauLink" id="meau1">comedies</a>
<ul class="meau" id="meau2">
<li><a href="page1.html">All is Well That Ends Well1</a></li>
<li><a href="page1.html">All is Well That Ends Well2</a></li>
<li><a href="page1.html">All is Well That Ends Well3</a></li>
<li><a href="page1.html">All is Well That Ends Well4</a></li>
</ul>
</div>
JS代码:
function toggleMeau1()
{
var link = document.getElementById("meau1");
var link1 = document.getElementById("meau2").style;
link.onmouseover = function()
{
link1.display = "block";
} //鼠标移动到链接上自动打开菜单
link.parentNode.onmouseout = function()
{
link1.display = "none";
}//鼠标移出层后自动关闭菜单
}
问题来了
鼠标离开链接后自动关闭了菜单,而我的原先设想是鼠标离开层后再自动关闭菜单。用css设置ul的display状态为none。鼠标移动到链接上打开的菜单难道就不算div的吗(这是本问题的重点,希望大神们详细解答下)?为了对比, 我又试了将代码改成进入层自动打开菜单,离开层关闭菜单,能达到鼠标离开层自动关闭菜单的效果。
JavaScript 自动弹出菜单问题
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1条回答 默认 最新
- Go 旅城通票 2016-05-18 13:35关注
用计时器延时执行隐藏操作,如果移动到菜单上就清楚掉计时器
你这种效果用css就能完毕,不需要用js,麻烦
<div> <a href="3" class="meauLink" id="meau1">comedies</a> <ul class="meau" id="meau2"> <li><a href="page1.html">All is Well That Ends Well1</a></li> <li><a href="page1.html">All is Well That Ends Well2</a></li> <li><a href="page1.html">All is Well That Ends Well3</a></li> <li><a href="page1.html">All is Well That Ends Well4</a></li> </ul> </div> <script> function toggleMeau1() { var link = document.getElementById("meau1"); var link1 = document.getElementById("meau2"); link1.onmouseover = function () { clearTimeout(timer); } link1.onmouseout = function (e) { e = e || window.event; var o = e.relatedTarget || e.toElement; do { if (o == this) return;//移动到子元素 } while (o = o.parentNode) this.style.display='none' } link.onmouseover = function () { link1.style.display = "block"; } //鼠标移动到链接上自动打开菜单 var timer link.onmouseout = function (e) { e = e || window.event; var o = e.relatedTarget || e.toElement; do { if (o == this) return;//移动到子元素 } while (o = o.parentNode) timer = setTimeout(function () { link1.style.display = "none"; }, 500); }//鼠标移出层后自动关闭菜单 } toggleMeau1() </script>
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