#include
#include
int visit(int, int);
//迷宫矩阵,2代表墙壁,0代表通道
int maze[7][7] = {{2, 2, 2, 2, 2, 2, 2},
{2, 0, 0, 0, 0, 0, 2},
{2, 0, 2, 0, 2, 0, 2},
{2, 0, 0, 2, 0, 2, 2},
{2, 2, 0, 2, 0, 2, 2},
{2, 0, 0, 0, 0, 0, 2},
{2, 2, 2, 2, 2, 2, 2}};
int startI = 1, startJ = 1; // 入口
int endI = 5, endJ = 5; // 出口
int success = 0;
int main(void)
{
int i, j;
printf("显示迷宫:\n");
for(i = 0; i < 7; i++)
{
for(j = 0; j < 7; j++)
{
if(maze[i][j] == 2)
printf("█");
else
printf(" ");
}
printf("\n");
}
if(visit(startI, startJ) == 0)
{
printf("\n没有找到出口!\n");
}
else
{
printf("\n显示路径:\n");
for(i = 0; i < 7; i++)
{
for(j = 0; j < 7; j++)
{
if(maze[i][j] == 2)
printf("█");
else if(maze[i][j] == 1)
printf("◇");
else
printf(" ");
}
printf("\n");
}
}
return 0;
}
int visit(int i, int j)
{
//该点走过,标记为1
maze[i][j] = 1;
//走到终点,成功
if(i == endI && j == endJ)
success = 1;
//向四个方向递归调用函数visit()
if(success != 1 && maze[i][j+1] == 0) visit(i, j+1);
if(success != 1 && maze[i+1][j] == 0) visit(i+1, j);
if(success != 1 && maze[i][j-1] == 0) visit(i, j-1);
if(success != 1 && maze[i-1][j] == 0) visit(i-1, j);
//该点走过,但没成功,则该点重新置为0
if(success != 1)
maze[i][j] = 0;
return success;
}
最后一句,该点走过,但没成功,则该点重新置为0,神魔意思啊,是回退一个格,还是回退多格,重新置零之后,又重新走了一边遍怎么办