JSON解析报错怎么解决？贴出错误和代码

{"res":"01","info":{"SongName":"L\u1ee1 y\u00eaubbbbbbbb","WordNum":"2","PyCode":"LY","Stroke":"0","SingerName1":"Hu\u1ef3nh Nh\u1eadt Huy","SingerName2":"","FileName":"2","Lang":"1","SongTypeID":"3","SingerID1":"123","SingerID2":"456","MType":"1","yTrack":"0","bTrack":"1","yVolume":"92","bVolume":"92","NewSong":"1","style":"9","SongNameSpell":"aaa","SingerNameSpell1":null,"SingerNameSpell2":null}}

这是我的JSON串
然后我的解析是这样做的

JSONObject obj = new JSONObject(response.toString());
JSONArray arr = obj.getJSONArray("info");
for (int i = 0; i < arr.length(); i++) {
JSONObject subObj = arr.getJSONObject(i);
String sn = subObj.getString("SongName");
String w = subObj.getString("WordNum");
String p = subObj.getString("PyCode");
String st = subObj.getString("Stroke");
String singer1 = subObj.getString("SingerName1");
。。。。。。。
然后打印出解析的JSON串
}

报错是
Value {"Lang":"1","yVolume":"92","MType":"1","SongNameSpell":"aaa","Stroke":"0","SongName":"Lỡ yêubbbbbbbb","SingerNameSpell1":null,"SingerNameSpell2":null,"yTrack":"0","SongTypeID":"3","PyCode":"LY","style":"9","bVolume":"92","FileName":"2","SingerName1":"Huỳnh Nhật Huy","WordNum":"2","SingerName2":"","SingerID2":"456","NewSong":"1","SingerID1":"123","bTrack":"1"}
at info of type org.json.JSONObject cannot be converted to JSONArray

请问这是什么情况求解答啊。。