JAVA解析JSON出错贴出错误信息和代码求解答

Question

我要解析的JSON response.toString()是:

{"res":"01","info":{"SongName":"L\u1ee1 y\u00eaubbbbbbbb","WordNum":"2","PyCode":"LY","Stroke":"0","SingerName1":"Hu\u1ef3nh Nh\u1eadt Huy","SingerName2":"","FileName":"2","Lang":"1","SongTypeID":"3","SingerID1":"123","SingerID2":"456","MType":"1","yTrack":"0","bTrack":"1","yVolume":"92","bVolume":"92","NewSong":"1","style":"9","SongNameSpell":"aaa","SingerNameSpell1":null,"SingerNameSpell2":null}}
然后解析的时候用
JSONObject obj = new JSONObject(response.toString());
String l = obj.getString("Lang");
String w = obj.getString("WordNum");
Log.i("解析后的数据 ", "WordNum" + w);
我这样写了之后后台打印出
没有Lang这个value,
然后经过注释（我没有全试）发现好像我打印哪个值都会有这样的提示 请问这是什么原因啊。。。

Answer 1

 JSONObject obj = new JSONObject(response.toString());
 JSONObject objInfo = obj.getJSONObject("info");
 String l = objInfo.getString("Lang");