安卓Android APP密码跳转activity

首界面为一个密码输入界面,输入密码正确后,按确定按钮,然后跳转activity。如何实现

12个回答

来个oncilck()登录验证啊,事件监听作数据判断正确intent跳转,错误toast输出下密码错误提示就行了

public void onClick(View v) { //监听
switch (v.getId()) {
case R.id.logButton://你的登录按钮id
//密码验证
.....
Intent intent = new Intent(this,DestinationActivity.class);//目标界面Activity: DestinationActivity
finish();
startActivity(intent);
break;
case ~~:
}
}


做onclick事件对密码进行验证 验证通过使用intent跳转activity,验证不通过就toast弹框提示“密码错误~”

实现 登陆按钮的点击事件
先行判断 判断 账号密码正确之后 再执行 页面跳转就行

button的onclick事件中对输入框的内容进行获取,之后进行对密码进行判断,密码正确就跳转

确定按钮设置点击事件,若密码正确则Intent跳转到要进入的activity

这就是一个登录界面,点击按钮,判断密码,正确则Intent跳转到,

我在登录界面一般就是把账号密码发给服务器,再让服务器返回数据,根据返回的状态,判断账号密码是否匹配,成功后,在用intent跳转

在按钮的onclick事件中判断下密码对不对就好了啊

activity里监听确定按钮:setOnClickListener(...){//这里效果密码的正确性,如果正确做跳转下一个activity的动作:Intent intent=new Intent(this,目标类);start就好了}

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PID: 384 SIG: 3rn05-06 02:48:37.902: INFO/dalvikvm(384): threadid=7: reacting to signal 3rn05-06 02:48:37.922: INFO/dalvikvm(384): Wrote stack trace to '/data/anr/traces.txt'rn05-06 02:48:42.392: WARN/KeyCharacterMap(52): No keyboard for id 0rn05-06 02:48:42.392: WARN/KeyCharacterMap(52): Using default keymap: /system/usr/keychars/qwerty.kcm.binrn05-06 02:48:52.102: INFO/Process(384): Sending signal. PID: 384 SIG: 9rn05-06 02:48:52.182: INFO/ActivityManager(52): Process com.tmxk (pid 384) has died.rn05-06 02:48:52.192: INFO/WindowManager(52): WIN DEATH: Window44dcaf50 com.tmxk/com.tmxk.ComsystemActivity paused=falsern05-06 02:48:52.252: INFO/UsageStats(52): Unexpected resume of com.android.launcher while already resumed in com.tmxkrn05-06 02:48:52.302: ERROR/gralloc(52): [unregister] handle 0x4a2368 still locked (state=40000001)rn05-06 02:48:52.322: WARN/InputManagerService(52): Got RemoteException sending setActive(false) notification to pid 384 uid 10034rn运行结果为the apploication has stopped exception
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