synchronized 线程同步

Question

public class Ticket extends Thread{
static int num = 0;
String name;
public Ticket(String name) {
this.name = name;
}
public synchronized void get(){
for(int i = 0;i<10;i++){
System.out.println(name+" "+num);
if(num==1000) return;
++num;
}

}
@Override
public  void run() {
    try {
        System.out.println(name+"*********** "+num);

            Thread.sleep(1000);

                get();  




    } catch (InterruptedException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}
public static void main(String[] args) {
    Thread t100 = new  Ticket("t100:");
    Thread t200 = new  Ticket("t200:");
    Thread t3 = new  Ticket("t3:");
    t100.start();
    t200.start();
    List<Thread> list = new ArrayList<Thread>();
    /*for(int i = 0;i<10;i++){
        //new Thread("t"+i+":").start();
       list.add(new Ticket("t"+i+":"));
    }
    for(int j = 0;j<list.size();j++){
        //System.out.println(list.get(j));
             list.get(j).start();
        }*/
}

一次运行正常显示 多次就乱了

Answer 1

死锁，同步
TestSync.java
package Thread;

public class TestSync implements Runnable{

Timer timer = new Timer();

public static void main(String[] args) {
    TestSync test = new TestSync();
    Thread t1 = new Thread(test);
    Thread t2 ......<br/><strong>答案就在这里：</strong><a target='_blank' rel='nofollow' href='http://blog.csdn.net/anskya520/article/details/6235493'>线程同步synchronized</a><br/>----------------------你好，人类，我是来自CSDN星球的问答机器人小C，以上是依据我对问题的理解给出的答案，如果解决了你的问题，望采纳。