看上别人网站上的一个循环倒计时,复制后发现网站上是可以自动3天循环倒计时,查了下代码发现看上的那个网站上代码里有两个值var serverTime和var Htime是一直在变的,我复制的源代码是固定值所以倒计时结束后就显示0 不会重新 倒计时。那两个值应该是php写的所以查看源代码时候只能看到结果。
求 下面着两个值的php代码应该怎么写(下面目前的值是我复制时候的值1000是固定的其他两组数字是一直在变的)
var serverTime = 1470186666 * 1000;
var Htime = 226134000;
时间代码如下(div和CSS没复制进来),目前是日期可以三天重新开始,倒计时就是那两个值不知道php代码是怎么求得的
<script type="text/javascript">
//var dateTimezz = new Date();
//alert(dateTimezz);
var serverTime = 1470186666 * 1000;
var Htime = 226134000;
jQuery(document).ready(function(){
//var dateTime = new Date('Sun Dec 04 2015 00:00:00');
//alert(dateTime.getTime());
var dateTime = new Date();
var difference = dateTime.getTime() - serverTime;
var endTime = new Date().getTime()+Htime-difference;
setInterval(function(){
jQuery(".tlimit").each(function(){
var obja = jQuery(this);
var dateTimez = new Date();
var strDateList = daysBetween('2015-12-06',(dateTimez.getYear()+1900)+'-'+(dateTimez.getMonth()+1)+'-'+dateTimez.getDate()).toLocaleString();
//var strDateList = daysBetween('2015-12-06','2015-12-19').toLocaleString();
var chaday = Math.ceil(strDateList/3)*3;
//alert(chaday);
var str2 = 'TIME LIMIT: '+dateAdd("d", chaday-2, '2015/12/06').toLocaleString()+' - '+dateAdd("d", chaday, '2015/12/06').toLocaleString();
obja.html(str2);
});
}, 10);
setInterval(function(){
jQuery(".t3").each(function(){
var obj = jQuery(this);
var dateTimea = new Date();
var nMS=endTime - dateTimea.getTime();
var myD=Math.floor(nMS/(1000 * 60 * 60 * 24));
var myH=Math.floor(nMS/(1000*60*60)) % 24;
var myM=Math.floor(nMS/(1000*60)) % 60;
var myS=Math.floor(nMS/1000) % 60;
if(myD>= 0){
myD = ( ( myD < 10 ) ? "0" : "")+myD;
myH = ( ( myH < 10 ) ? "0" : "")+myH;
myM = ( ( myM < 10 ) ? "0" : "")+myM;
myS = ( ( myS < 10 ) ? "0" : "")+myS;
var str = '<i class="d">Day<br><b>' + myD+'</b></i><i class="h">Hou<br><b>'+myH+'</b></i><i class="m">Min<br><b>'+myM+'</b></i><i class="s">Sec<br><b>'+myS+'</b></i>';
}else{
var str = '<i class="d">Day<br><b>00</b></i><i class="h">Hou<br><b>00</b></i><i class="m">Min<br><b>00</b></i><i class="s">Sec<br><b>00</b></i>';
}
obj.html(str);
});
}, 10);
});
function daysBetween(DateOne,DateTwo)
{
var OneMonth = DateOne.substring(5,DateOne.lastIndexOf ('-'));
var OneDay = DateOne.substring(DateOne.length,DateOne.lastIndexOf ('-')+1);
var OneYear = DateOne.substring(0,DateOne.indexOf ('-'));
var TwoMonth = DateTwo.substring(5,DateTwo.lastIndexOf ('-'));
var TwoDay = DateTwo.substring(DateTwo.length,DateTwo.lastIndexOf ('-')+1);
var TwoYear = DateTwo.substring(0,DateTwo.indexOf ('-'));
var cha=((Date.parse(OneMonth+'/'+OneDay+'/'+OneYear)- Date.parse(TwoMonth+'/'+TwoDay+'/'+TwoYear))/86400000);
return Math.abs(cha);
}
function dateAdd(strInterval, NumDay, dtDate) {
var dtTmp = new Date(dtDate);
if (isNaN(dtTmp)) dtTmp = new Date();
var ddTmp = new Date(Date.parse(dtTmp) + (86400000 * NumDay));
return (ddTmp.getYear()+1900)+'.'+(ddTmp.getMonth()+1)+'.'+ddTmp.getDate();
/*switch (strInterval) {
case "s":return new Date(Date.parse(dtTmp) + (1000 * NumDay));
case "n":return new Date(Date.parse(dtTmp) + (60000 * NumDay));
case "h":return new Date(Date.parse(dtTmp) + (3600000 * NumDay));
case "d":return ((new Date(Date.parse(dtTmp) + (86400000 * NumDay))).getYear()+1900)+'.'+((new Date(Date.parse(dtTmp) + (86400000 * NumDay))).getMonth()+1)+'.'+(new Date(Date.parse(dtTmp) + (86400000 * NumDay))).getDate();
case "w":return new Date(Date.parse(dtTmp) + ((86400000 * 7) * NumDay));
case "m":return new Date(dtTmp.getFullYear(), (dtTmp.getMonth()) + NumDay, dtTmp.getDate(), dtTmp.getHours(), dtTmp.getMinutes(), dtTmp.getSeconds());
case "y":return new Date((dtTmp.getFullYear() + NumDay), dtTmp.getMonth(), dtTmp.getDate(), dtTmp.getHours(), dtTmp.getMinutes(), dtTmp.getSeconds());
} */
}
</script>