无法用iterator遍历vector<char *>怎么办

Question

#include
#include
using namespace std;
int main()
{
vector ivec;
char name[20];
cout << "请输入字符串" << endl;
while (cin >> name)
ivec.push_back(name);
for (vector::iterator it = ivec.begin(); it != ivec.end(); it ++)
cout << *it << endl;
cout << ivec.size() << endl;
cout << endl;
return 0;
}

运行结果为:
请输入字符串
ii jj kk
~Z

3

请按任意键继续......
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Answer 1

 #include <iostream>
#include <vector>
using namespace std;
int main()
{
vector<char *> ivec;
int i = 0;
char name[100][20];
        cout << "请输入字符串" << endl;
while (cin >> name[i])
ivec.push_back(name[i++]);
for (vector<char *>::iterator it = ivec.begin(); it != ivec.end(); it ++)
cout << *it << endl;
cout << ivec.size() << endl;
cout << endl;
return 0;
}

Answer 2

你那么写，根本只有一个字符串数组，所以输入了后面的，冲掉了前面的。