Android 中的搜索功能在程序中可以执行。我使用 onSearchRequested();来调用搜索功能
现在我不想使用onSearchRequested(); 把一个字符串从一个 EditText 传递到 search 方法中，并把结果显示在list中。
当调用onSearchRequested时，search 方法可以运行。
SearchPage Activity:
DBHelper = new DBAdapter(this);
DBHelper.open();
Intent intent = getIntent();
if (Intent.ACTION_SEARCH.equals(intent.getAction())) {
String query = intent.getStringExtra(SearchManager.QUERY);
showResults(query);
}
private void showResults(String query) {
Cursor cursor = DBHelper.searchDB(query);
startManagingCursor(cursor);
String[] searchFrom = new String[] { DBAdapter.KEY_YEAR,
DBAdapter.KEY_MAKE, DBAdapter.KEY_MODEL };
int[] displayHere = new int[] { R.id.rYearTV, R.id.rMakeTV,
R.id.rModelTV };
final SimpleCursorAdapter records = new SimpleCursorAdapter(this,
R.layout.record_2, cursor, searchFrom, displayHere);
setListAdapter(records);
DBAdapter Activity:
//--- 从 search 中获得 records
public Cursor searchDB(String query) {
String[] parts = query.split(" ");
String queryString = "";
for(int i = 0; i < parts.length; i++) {
queryString += KEY_YEAR + " LIKE '%" + parts[i] + "%' OR ";
queryString += KEY_MAKE + " LIKE '%" + parts[i] + "%' OR ";
queryString += KEY_MODEL + " LIKE '%" + parts[i] + "%'";
if(i != (parts.length - 1)) {
queryString += " OR ";
}
}
return db.query(true, DB_TABLE,
new String[] { KEY_ROWID, KEY_SDATE, KEY_YEAR, KEY_MAKE, KEY_MODEL },
queryString, null, null, null, null, null);
}
//--- 从 Search 中获取 Records
我想传递一个字符串到 search 函数 String searchData = searchEditText.getText().toString();，点击 "Search"按钮，search 函数可以正常运行。如何开始？
