c语言链表问题，求助啊

Question

#include
#include

typedef struct node
{
char name[100];
int score;
struct node *next;
}StudList;

void CreateStudent(StudList **sl)
{
int n;
StudList s, *tu;
sl = (StudList)malloc(sizeof(StudList));
tu = sl;
printf("学生人数:");
scanf("%d", &n);
for (int i = 0; i < n; i++)
{
s = (StudList *)malloc(sizeof(StudList));
printf("第%d个学生姓名和成绩:", i + 1);
scanf("%s-%d", s->name,&s->score);
//scanf("%d", &s->score);
tu->next = s;
tu = s;
}
tu->next = NULL;
}

void DispList(StudList *L)
{
StudList *p = L->next;
printf(" 名次 姓名 成绩\n");
int i = 1;
while (p != NULL)
{
printf(" %d\t\t", i++);
printf("%s\t\t", p->name);//有错
printf("%d\n", p->score);
p = p->next;
}
}

int main()
{
StudList *n;
printf("建立学生表\n");
CreateStudent(&n);
DispList(&n);

system("pause");
return 0;

}

大神们，我每次运行的时候都提示我注释的地方有异常，谁能帮我调一下，有赏啊，兄弟们

Answer 1

你这代码 问题很多
DispList(&n); &n 是 StudList** 类型 而你的函数 原型 需要 StudList* 类型
scanf("%s-%d", s->name,&s->score); 好像 并不能正确的输入
sl = (StudList)malloc(sizeof(StudList)); 这类型 都不一致 不知道你怎么能编译不报错呢