#include
using namespace std;
int main()
{
unsigned char a[3];
a[0] = 251;
a[1] = 3;
a[2] = 0;
int i = 0;
cout << a[i++] + a[i++] * 256 << endl;
}
在redhat6.1中结果和vs2013中是64507,而在cetos中是1019,求解答
#include
using namespace std;
int main()
{
unsigned char a[3];
a[0] = 251;
a[1] = 3;
a[2] = 0;
int i = 0;
cout << a[i++] + a[i++] * 256 << endl;
}
在redhat6.1中结果和vs2013中是64507,而在cetos中是1019,求解答
从结果倒推可知两种编译器对i++的处理方式不一样
前两者都是语句结束后才自增(相当于a[0] + a[0] * 256)
后者直接自增(相当于a[0] + a[1] * 256)