java只用两个for循环输出N个菱形

Question

这道题小弟完全没有思路，空格和星号都已经占了两个循环！如何只利用两个循环来做？我用字符数组弄出来了！但是老师说不能运用超前的知识！求帮忙！
附上运用数组实现代码：
Scanner scanner = new Scanner(System.in);
System.out.print("请输入要输出的行数：");
int a =scanner.nextInt();
String t[] = new String[6];
t[1] = " ";
t[2] = " **";
t[3] = " *****";
t[4] = " *******";
t[5] = "*********";
int i=1;
int flag=0;
int count=0;
do{
for(i=1;i<=5;i++){
if(count==a){
flag=1;
break;
}
count++;
System.out.println(t[i]);
}
for(int m=4;m>=2;m--){
if(count==a){
flag=1;
break;
}
count++;
System.out.println(t[m]);
}
}while(flag==0);

Answer 1

一个循环就可以了
规律 1 3 5 7 9 7 5 3 每8个循环一次

 #include<stdio.h>
int main()
{
    int n;
    scanf("%d",&n);
    for (int i = 1; i <= n; i++)
    {
        int a = i%8;
        if(a == 1) 
        {
            printf("    *\n");
        }
        if(a == 2) 
        {
            printf("   ***\n");
        }
        if(a == 3 || a == 7) 
        {
            printf("  *****\n");
        }
        if(a == 4 || a == 6) 
        {
            printf(" *******\n");
        }
        if(a == 5) 
        {
            printf("*********\n");
        }

    }

    return 0;   
}