移位运算符在输出的时候运算和运算后输出的结果为什么不一样

Question

#include
#include
using namespace std;
void bit_print(unsigned short t);
int main()
{
unsigned short a=34520;
unsigned short b=a<>8;
printf("%d \n",b|c);
printf("%d \n",(a<>8));
return 0;
}

Answer 1

每次移位运算后变量本身的值都会被修改