请问c语言中使用模块化为什么会导致结果不同？

Question

这个是不使用模块化的程序
#include
#include
#include
int main(void)
{
int ch, word, alpha;
double result;
alpha = word = 0;
bool inword = false;

while ((ch = getchar()) != EOF)
{
    if (isalpha(ch))
        alpha++;
    if (isalpha(ch) && !inword)
    {
        inword = true;
        word++;
    }
    if (!isalpha(ch) && inword)
        inword = false;
}
result = alpha / word;
printf("%d word and %d alpha,per %.2lf alpha in a word.", word, alpha, result);
getchar();
getchar();
return 0;

}
调试结果正常
然后我使用模块化
#include
#include
#include
int get_word(char ch);
int get_alpha(char ch);
int main(void)
{
int ch,word,alpha;
double result;

while ((ch = getchar()) != '#')
{
    word = get_word(ch);
    alpha = get_alpha(ch);
}
result = (float)alpha / (float)word;
printf("%d word and %d alpha,per %.2lf alpha in a word.", word, alpha,result );
getchar();
getchar();
return 0;

}

int get_word(char ch)
{

int word1=0;
bool inword = false;
if (isalpha(ch) && !inword)
{
    inword = true;
    word1++;
}
if (!isalpha(ch)&&inword)
    inword = false;
return word1;

}

int get_alpha(char ch)
{

int alpha1=0;
if (isalpha(ch))
    alpha1++;
return alpha1;

}
调试结果全是1
请问这是怎么回事？

Answer 1

bool inword = false;

int get_word(char ch)
{
int word1=0;

if (isalpha(ch) && !inword)
{
inword = true;
word1++;
}
if (!isalpha(ch)&&inword)
inword = false;
return word1;
}
int get_alpha(char ch)
{
int alpha1=0;
if (isalpha(ch))
alpha1++;
return alpha1;
}

int main(void)
{
int ch,word = 0,alpha = 0;
double result;
while ((ch = getchar()) != '#')
{
word += get_word(ch);
alpha += get_alpha(ch);
}
result = (float)alpha / (float)word;
printf("%d word and %d alpha,per %.2lf alpha in a word.", word, alpha,result );
getchar();
getchar();
return 0;
}