LZOXAnn 2016-11-29 08:13 采纳率: 14.3%
浏览 4612
已采纳

button 的onclick事件怎么也不触发。请帮忙。谢谢




<html>
<head>
<script language="JavaScript" type="text/javascript">

function butRemoveWed_onclick()
{
  if (document.form1.theDay.options[2].text == "Wednesday")
   {
      document.form1.theDay.options[2]=null;
    }
 else
   {
      alert("There is no Wednesday here!");
   }
}


function butAddWed_onclick()
{
   if (document.form1.theDay.options[2].text != Wednesday")
      {
         var indexCounter;
         var days=document.form1.theDay;
         var lastoption=new option();
         days.options[6]=lastoption;
         for (indexCounter=6; indexCounter>2; indexCounter--)
             {
                days.options[indexCounter].text=days.options[indexCounter-1].text;
                days.options[indexCounter].value=days.options[indexCounter-1].value;
              }
          var option=new option ("Wednesday",2);
          days.options[2]=option;
        }
    else
       {
           alert("Do you want to have TWO Wednesdays?????");
        }
}
</script>
</head>
<body>
<form name=form1>
<select name=theDay size=5>
  <option value=0 selected>Monday
  <option value=1>Tuesday
  <option value=2>Wednesday
  <option value=3>Thursday
  <option value=4>Friday
  <option value=5>Saturday
  <option value=6>Sunday
</select>

<input type="button" value="Remove Wednesday" name=butRem onclick="butRemoveWed_onclick()">
<input type="button" value="Add Wednesday" name=butAd onclick="butAddWed_onclick()">


</form>
</body>
</html>
  • 写回答

7条回答 默认 最新

  • Go 旅城通票 2016-11-29 08:28
    关注
    

        function butAddWed_onclick() {
            if (document.form1.theDay.options[2].text != "Wednesday")/////////////少了引号
            {
                var indexCounter;
                var days = document.form1.theDay;
                var lastoption = new Option();//////没注意大小写
                days.options[6] = lastoption;
                for (indexCounter = 6; indexCounter > 2; indexCounter--) {
                    days.options[indexCounter].text = days.options[indexCounter - 1].text;
                    days.options[indexCounter].value = days.options[indexCounter - 1].value;
                }
                var option = new Option("Wednesday", 2);;//////没注意大小写
                days.options[2] = option;
            }
            else {
                alert("Do you want to have TWO Wednesdays?????");
            }
        }
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(6条)

报告相同问题？

悬赏问题

  • ¥15 安卓adb backup备份应用数据失败
  • ¥15 eclipse运行项目时遇到的问题
  • ¥15 关于#c##的问题：最近需要用CAT工具Trados进行一些开发
  • ¥15 南大pa1 小游戏没有界面，并且报了如下错误，尝试过换显卡驱动，但是好像不行
  • ¥15 没有证书，nginx怎么反向代理到只能接受https的公网网站
  • ¥50 成都蓉城足球俱乐部小程序抢票
  • ¥15 yolov7训练自己的数据集
  • ¥15 esp8266与51单片机连接问题(标签-单片机|关键词-串口)（相关搜索：51单片机|单片机|测试代码）
  • ¥15 电力市场出清matlab yalmip kkt 双层优化问题
  • ¥30 ros小车路径规划实现不了，如何解决？(操作系统-ubuntu)