LZOXAnn 2016-11-29 08:13 采纳率: 14.3%
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button 的onclick事件怎么也不触发。请帮忙。谢谢




<html>
<head>
<script language="JavaScript" type="text/javascript">

function butRemoveWed_onclick()
{
  if (document.form1.theDay.options[2].text == "Wednesday")
   {
      document.form1.theDay.options[2]=null;
    }
 else
   {
      alert("There is no Wednesday here!");
   }
}


function butAddWed_onclick()
{
   if (document.form1.theDay.options[2].text != Wednesday")
      {
         var indexCounter;
         var days=document.form1.theDay;
         var lastoption=new option();
         days.options[6]=lastoption;
         for (indexCounter=6; indexCounter>2; indexCounter--)
             {
                days.options[indexCounter].text=days.options[indexCounter-1].text;
                days.options[indexCounter].value=days.options[indexCounter-1].value;
              }
          var option=new option ("Wednesday",2);
          days.options[2]=option;
        }
    else
       {
           alert("Do you want to have TWO Wednesdays?????");
        }
}
</script>
</head>
<body>
<form name=form1>
<select name=theDay size=5>
  <option value=0 selected>Monday
  <option value=1>Tuesday
  <option value=2>Wednesday
  <option value=3>Thursday
  <option value=4>Friday
  <option value=5>Saturday
  <option value=6>Sunday
</select>

<input type="button" value="Remove Wednesday" name=butRem onclick="butRemoveWed_onclick()">
<input type="button" value="Add Wednesday" name=butAd onclick="butAddWed_onclick()">


</form>
</body>
</html>
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7条回答

  • Go 旅城通票 2016-11-29 08:28
    关注
    

        function butAddWed_onclick() {
            if (document.form1.theDay.options[2].text != "Wednesday")/////////////少了引号
            {
                var indexCounter;
                var days = document.form1.theDay;
                var lastoption = new Option();//////没注意大小写
                days.options[6] = lastoption;
                for (indexCounter = 6; indexCounter > 2; indexCounter--) {
                    days.options[indexCounter].text = days.options[indexCounter - 1].text;
                    days.options[indexCounter].value = days.options[indexCounter - 1].value;
                }
                var option = new Option("Wednesday", 2);;//////没注意大小写
                days.options[2] = option;
            }
            else {
                alert("Do you want to have TWO Wednesdays?????");
            }
        }
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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