AtomicStampedReference解决ABA的问题

Question

public class AtomicStampedReferenceTest {
public final static AtomicStampedReference ATOMIC_REFERENCE = new AtomicStampedReference("abc" ,0);

public static void main(String []args) {
    for(int i = 0 ; i < 100 ; i++) {
        final int num = i;
        final int stamp = ATOMIC_REFERENCE.getStamp();
        new Thread() {
            public void run() {
                try {
                    Thread.sleep(Math.abs((int)(Math.random() * 100)));
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
                //时间戳初始化为0 然后每次进行判断当前的值是否为0 然后判断当前值是否为abc 同时满足的话则吧值修改成abc2 时间戳改成1
                if(ATOMIC_REFERENCE.compareAndSet("abc" , "abc2" , stamp , stamp + 1)) {
                    System.out.println("我是线程：" + num + ",我获得了锁进行了对象修改！"+ATOMIC_REFERENCE.getStamp());
                }
               System.out.println(stamp);//这里会一直输出1  不会输出2  下面的线程不是修改成2了么 ？？？？
            }
        }.start();
    }
    new Thread() {
        public void run() {
            int stamp = ATOMIC_REFERENCE.getStamp();
            //
            while(!ATOMIC_REFERENCE.compareAndSet("abc2", "abc" , stamp , stamp + 1));
            System.out.println("已经改回为原始值！"+ ATOMIC_REFERENCE.getStamp());
        }
    }.start();
}

}

对？？？？标注的地方不是很明白 还望各位指教

Answer 1

你启动了100个线程，下方的线程加上就是101个，这样就会有100个线程输出1，一个线程输出2，所以建议你，先改一改代码吧