pyqt4下函数未经触发就自动运行，且窗体不显示。

Question

本来应该显示出“重启”和“停止重启”的对话框，但在键入self.connect(）后不知道为什么就直接运行send()函数了？

class Dlg(QtGui.QDialog):
    def __init__(self,parent=None):
        # super(Dlg,self).__init__(parent)
        QtGui.QDialog.__init__(self,parent)
        self.init()
def init(self):
        self.setWindowTitle(u"服务器重启程序")
        # self.setGeometry(20,100)
        Button1=QtGui.QPushButton(u"重启",self)       
        Button2=QtGui.QPushButton(u"停止重启",self)     
        gridLayout=QtGui.QGridLayout()
        gridLayout.addWidget(Button1,0,0)
        gridLayout.addWidget(Button2,0,1)
        self.setLayout(gridLayout)
        # time.sleep(10)
        self.connect(Button1,QtCore.SIGNAL("clicked()"),self.send(1))
        self.connect(Button2,QtCore.SIGNAL("clicked()"),self.send(2))
def send(self,mes):
        print "send"
        if mes==1:
            mes="reboot"
        if mes==2:
            mes="stop"
        s=socket.socket()
        host="192.168.6.2"
        port=12345
        s.connect((host,port))
        s.send(mes)
app=QtGui.QApplication(sys.argv)
dialog=Dlg()
dialog.show()
app.exec_()

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Answer 1

http://www.cnblogs.com/moonlightpoet/p/5327107.html