能解释解释这里有关p的变化吗

Question

1. What is the output of this C code?

   #include
   int main()
   {
   int i = 10;
   int *p = &i;
   foo(&p);
   printf("%d ", *p);
   printf("%d ", *p);
   }
   void foo(int **const p)
   {
   int j = 11;
   *p = &j;
   printf("%d ", **p);
   }
   a) 11 11 11
   b) 11 11 Undefined-value
   c) Compile time error
   d) Segmentation fault/code-crash
   View Answer

Answer:b

Answer 1

    int i = 10;
    int *p = &i;
    foo(&p);
    printf("aadfa");
    printf("%d ", *p);  //
    printf("%d ", *p); // 

    这两个输出都是未知数。。应为foo的内部变量已经释放完全，*p等于野指针。。