Gestirn 2017-01-14 05:40 采纳率: 0%
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已结题

eclipse中jsp到Servlet报出异常NoClassDefFoundError

 exception 
javax.servlet.ServletException: Servlet execution threw an exception
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)



root cause 
java.lang.NoClassDefFoundError: org/apache/lucene/index/CorruptIndexException
    servlet.SearcherServlet.doGet(SearcherServlet.java:44)
    servlet.SearcherServlet.doPost(SearcherServlet.java:59)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:650)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:731)
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)



root cause 
java.lang.ClassNotFoundException: org.apache.lucene.index.CorruptIndexException
    org.apache.catalina.loader.WebappClassLoaderBase.loadClass(WebappClassLoaderBase.java:1892)
    org.apache.catalina.loader.WebappClassLoaderBase.loadClass(WebappClassLoaderBase.java:1735)
    servlet.SearcherServlet.doGet(SearcherServlet.java:44)
    servlet.SearcherServlet.doPost(SearcherServlet.java:59)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:650)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:731)
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)

下面是Servlet

 protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {



        String service = request.getParameter("action");

        if (service.equals("eins")) {
            String key=request.getParameter("input");
            //System.out.println(key);
            Searcher seacher=new Searcher();        //这是第44行
            List<Movie> list=seacher.searchByFuzzy(key);
            request.setAttribute("movies", list);
            request.getRequestDispatcher("/Results.jsp").forward(
                    request, response);

        }

    }
  • 写回答

6条回答 默认 最新

  • JE_GE 2017-01-14 05:53
    关注

    缺少java.lang.NoClassDefFoundError: org/apache/lucene/index/CorruptIndexException,怎样跑

    评论

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