Head First Java 里面的专家术语学习机如何修改某个词出现的几率？

Question

     public class PhraseOMatic//注意不能再字符串“”中间加换行符，否则不能编译并运行  
    {  
        public static void main (String[] args){
            String [] name = {"小鸟","雷洛","核桃","AL","土豆","不二"};
            String [] diyiju = {"今天早上","今天中午","今天晚上","今天下午","今天凌晨"};
            String [] dierju = {"在路边","在沙滩上","在河边","在山上","在超市里","在空中"};
            String [] disanju = {"和蚂蚁跳舞。","和便便亲嘴。","和蚂蚱赛跑。","和兔子吃烧烤。"};
            //计算每一组有多少个名词术语
            int mingzi = name.length;
            int diyi = diyiju.length;
            int dier = dierju.length;
            int disan = disanju.length;

            //产生随机数字
            int ming = (int) (Math.random()*mingzi);
            int yi = (int) (Math.random()*diyi);
            int er = (int) (Math.random()*dier);
            int san = (int) (Math.random()*disan);

            //组合出扯淡的句子
            String phrase = name[ming]+diyiju[yi]+dierju[er]+disanju[san];

            System.out.println(phrase);
        }
    }  

Answer 1

给每一个词加权。
这段代码其实是从0~length 中随机到一个下标 然后拼接。
比如你要使{"小鸟","雷洛","核桃","AL","土豆","不二"};这么中的小鸟出现的概率大一点，
你就可以从0~2*length的范围去取随机数，然后0~length 都是取小鸟，其余的对应。
如果概率很复杂，那么就得用很复杂的if else 去匹配，
建议写一个方法，String getOne(String[] value, double[] weight)去解决
第二个参数是权重