jtanjing25
阿茶_Jonas
采纳率100%
2017-02-28 07:27

Head First Java 里面的专家术语学习机如何修改某个词出现的几率?

已采纳
     public class PhraseOMatic//注意不能再字符串“”中间加换行符,否则不能编译并运行  
    {  
        public static void main (String[] args){
            String [] name = {"小鸟","雷洛","核桃","AL","土豆","不二"};
            String [] diyiju = {"今天早上","今天中午","今天晚上","今天下午","今天凌晨"};
            String [] dierju = {"在路边","在沙滩上","在河边","在山上","在超市里","在空中"};
            String [] disanju = {"和蚂蚁跳舞。","和便便亲嘴。","和蚂蚱赛跑。","和兔子吃烧烤。"};
            //计算每一组有多少个名词术语
            int mingzi = name.length;
            int diyi = diyiju.length;
            int dier = dierju.length;
            int disan = disanju.length;

            //产生随机数字
            int ming = (int) (Math.random()*mingzi);
            int yi = (int) (Math.random()*diyi);
            int er = (int) (Math.random()*dier);
            int san = (int) (Math.random()*disan);

            //组合出扯淡的句子
            String phrase = name[ming]+diyiju[yi]+dierju[er]+disanju[san];

            System.out.println(phrase);
        }
    }  
  • 点赞
  • 写回答
  • 关注问题
  • 收藏
  • 复制链接分享
  • 邀请回答

2条回答

  • miaoch miaoch 4年前

    给每一个词加权。
    这段代码其实是从0~length 中随机到一个下标 然后拼接。
    比如你要使{"小鸟","雷洛","核桃","AL","土豆","不二"};这么中的小鸟出现的概率大一点,
    你就可以从0~2*length的范围去取随机数,然后0~length 都是取小鸟,其余的对应。
    如果概率很复杂,那么就得用很复杂的if else 去匹配,
    建议写一个方法,String getOne(String[] value, double[] weight)去解决
    第二个参数是权重

    点赞 1 评论 复制链接分享
  • miaoch miaoch 4年前
    //组合出扯淡的句子
            String phrase1 = getOne(name, new int[]{0,0,0,0,0,1}) +
                        getOne(diyiju, new int[]{0,0,0,1,0}) +
                        getOne(dierju, new int[]{0,1,0,0,0,1}) +
                        getOne(disanju, new int[]{1,0,0,0});
            //组合出扯淡的句子
            String phrase2 = getOne(name, new double[]{0,0,0.1,0.2,0.3,0.4}) +
                    getOne(diyiju, new double[]{0.1,0.1,0.1,0.1,0.6}) +
                    getOne(dierju, new double[]{0.25,0.1,0.1,0.25,0.15,0.15}) +
                    getOne(disanju, new double[]{0.2,0.2,0.25,0.25});
     public static String getOne(String[] values, int[] weights) {
            int sum = 0;
            for (int weight:weights) {
                sum += weight;
            }
            double weight = 0;
            double ran = Math.random();
            for (int i=0; i<weights.length; i++) {
                weight += weights[i]*1.0/sum;
                if (weight >= ran) {
                    return values[i];
                }
            }
            return values[values.length - 1];
        }
    
        public static String getOne(String[] values, double[] weights) {
            double weight = 0;
            double ran = Math.random();
            for (int i=0; i<weights.length; i++) {
                weight += weights[i];
                if (weight >= ran) {
                    return values[i];
                }
            }
            return values[values.length - 1];
        }
    
    点赞 评论 复制链接分享

相关推荐