大神帮帮忙，小白很慌张

Question

编程利用循环打印如下字符图形：
12345678987654321
234567898765432
3456789876543
45678987654
567898765
6789876
78987
898
9
我的代码如下：
#include
void main()
{
int a,sum;
sum=1;
for(a=1;a<=9;a++)
{
sum=sum+1;
printf("%d",sum);
}
for(a=1;a<=8;a++)
{
sum=sum-1;
printf("%d\n",sum);
}
sum=2;
for(a=1;a<=8;a++)
{
sum=sum+1;
printf("%d",sum);
}
for(a=1;a<=7;a++)
{
sum=sum-1;
printf("%d\n",sum);
}
sum=3;
for(a=1;a<=7;a++)
{
sum=sum+1;
printf("%d",sum);
}
for(a=1;a<=6;a++)
{
sum=sum-1;
printf("%d\n",sum);
}
sum=4;
for(a=1;a<=6;a++)
{
sum=sum+1;
printf("%d",sum);
}
for(a=1;a<=5;a--)
{
sum=sum+1;
printf("%d\n",sum);
}
sum=5;
for(a=1;a<=5;a++)
{
sum=sum+1;
printf("%d",sum);
}
for(a=1;a<=4;a++)
{
sum=sum-1;
printf("%d\n",sum);
}
sum=6;
for(a=1;a<=4;a++)
{
sum=sum+1;
printf("%d",sum);
}
for(a=1;a<=3;a++)
{
sum=sum-1;
printf("%d\n",sum);
}
sum=7;
for(a=1;a<=3;a++)
{
sum=sum+1;
printf("%d",sum);
}
for(a=1;a<=2;a++)
{
sum=sum-1;
printf("%d\n",sum);
}
sum=8;
for(a=1;a<=2;a++)
{
sum=sum+1;
printf("%d",sum);
}
for(a=1;a<=1;a++)
{
sum=sum-1;
printf("%d\n",sum);
}
sum=9;
printf("%d",sum);
}

Answer 1

这其实只要两层循环就可以了吧