指针b为什么会变？？？

Question

Answer 1

#include <stdio.h>
#include <malloc.h>
#include <iostream>

void func( char * w, int m )
{
    printf( "%s \n", w );
    printf( "w -> %p \n", w );
    char * a = w;
    char * b = w;

    printf( "a -> %p \nb -> %p\n", a, b );
    for( int i = 0; i < m; ++i )
        *w++;

    printf( "%s \n", w );
    printf( "w -> %p \n", w );
    printf( "a -> %p \nb -> %p\n", a, b );

    while( *w )
    {
        *a++ = *w++;
    }
    printf( "%s \n", a );
    printf( "%s \n", b );
    printf( "w -> %p \n", w );
    printf( "a -> %p \nb -> %p\n", a, b );
}

int main( int argc, char ** argv )
{
    char w[] = "ABCDEFG";
    func( w, 2 );


    system("pause");
    return 0;
}

a 和 b本来指向同一块地址，b指向的内存位置一直没变，但是上面的while里a将这块内存的内容改了！