C#语言，16进制与或问题操作

Question

数组byte[] data={00,00,00,00,00,00,00,00}是16进制，数组中第一个元素，16进制00，按button1，第一个与80，变成{80,00,00,00,00,00,00,00}。按button2，第一个再与40，变成{C0,00,00,00,00,00,00,00}，下button3，第二个元素与40，变成{C0,40,00,00,00,00,00,00}，这个算法怎么写？

Answer 1

直接^操作就行了

   public static byte[] data = { 00, 00, 00, 00, 00, 00, 00, 00 };
    public void Button1_Click(object sender, EventArgs e)
    {
        data[0] = (byte)(data[0] ^ 0x80);
        OutPutData();
    }
    public void Button2_Click(object sender, EventArgs e)
    {
        data[0] = (byte)(data[0] ^ 0x40);
        OutPutData();
    }
    public void Button3_Click(object sender, EventArgs e)
    {
        data[1] = (byte)(data[1] ^ 0x40);
        OutPutData();
    }
    public void OutPutData()
    {
        for (int i = 0; i < data.Length; i++) Response.Write(data[i] + "　");
    }