关于c++输入流的问题,百度后仍然无法解决我的问题
 #include<iostream>
#include<ctime>
using namespace std;

struct Car
{
    char name[500];
    int year;
};
int main()
{
    int num;
    //int ch;
    cout << "how many cars do you wish to catalog?";
    cin >> num;
    //ch=cin.get();
    //cout << ch << endl;
    //while (cin.get() != '\n');
    Car *car = new Car[num];
    for (int i = 0; i < num; i++)
    { 
        cout << "Car #" << i + 1 << ":" << endl;
        cout << "please enter the make: ";
        cin.get(car[i].name,500);
        //cin.get();
        //cin.getline(car[i].name, 500).get();
        cout << "please enter the year made: ";
        cin >> car[i].year;
        //cin.get();
        //while (cin.get() != '\n');
    }
    cout << "hear is you collection: " << endl;
    for (int i = 0; i < num; i++)
        cout << car[i].year << " " << car[i].name << endl;
    delete[]car;
    return 0;
}

以上注释是问题的解决方案,使用cin.get()就可以解决问题,我会用,但是我不知道原理以及为什么出错

图片说明

6个回答

 struct Car
{
    char name[500];
    int year;
};
int main()
{
    int num;
    //int ch;
    cout << "how many cars do you wish to catalog?\n";
    cin >> num;
    //ch=cin.get();
    //cout << ch << endl;
    //while (cin.get() != '\n');
    Car *car = new Car[num];
    for (int i = 0; i < num; i++)
    { 
        cout << "Car #" << i + 1 << ":" << endl;
        cout << "please enter the make: ";
        cin >> car[i].name;
        //cin.get();
        //cin.getline(car[i].name, 500).get();
        cout << "please enter the year made: ";
        cin >> car[i].year;
        //cin.get();
        //while (cin.get() != '\n');
    }
    cout << "hear is you collection: " << endl;
    for (int i = 0; i < num; i++)
        cout << car[i].year << " " << car[i].name << endl;
    delete[]car;
    return 0;
}

#include

#include
#include
using namespace std;

struct Car
{
char name[500];
int year;
};
int main()
{
int num;
cout << "how many cars do you wish to catalog?";
scanf("%d",&num);
Car *car = new Car[num];
for (int i = 0; i < num; i++)
{
cout << "Car #" << i + 1 << ":" << endl;
cout << "please enter the name: ";
scanf("%s",car[i].name);
cout << "please enter the year made: ";
car[i].year=cin.get();
scanf("%d",&car[i].year);

}
cout << "hear is you collection: " << endl;
for (int i = 0; i < num; i++)
    cout <<"Car #" <<i+1<<" "<<car[i].year << " " << car[i].name << endl;
delete[]car;
return 0;

}

图片说明

主要是文件流判断结束标志的问题

cin.get(car[i].name,500);//获取长度为500的文件流??
//cin.get();//先获取文件流
//cin.getline(car[i].name, 500).get();//然后根据行将文件流读取到字符数组中
//所以第二种方法应该没问题!!

istream& get (char* s, streamsize n);

Extracts characters from the stream and stores them in s as a c-string, until either (n-1) characters have been extracted or the delimiting >character is encountered: the delimiting character being either the newline character ('\n') or delim (if this argument is specified).
The delimiting character is not extracted from the input sequence if found, and remains there as the next character to be extracted from the stream (see getline for an alternative that does discard the delimiting character).
A null character ('\0') is automatically appended to the written sequence if n is greater than zero, even if an empty string is extracted.
istream

这两者的区别就在于行尾的换行符而已。cin.get(car[i].name,500);不读取换行符,所以需要一个额外的get()读取并抛弃之。
代码如下修改就可以正常运行了

  for (int i = 0; i < num; i++)
    { 
        cout << "Car #" << i + 1 << ":" << endl;
        cout << "please enter the make: ";
        cin.get();
        cin.get(name,500,'\n');
        cin.get();
        cout << "please enter the year made: ";
        cin >> year;

    }
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