 Paper Cut

Problem Description
Still remember those games we played in our childhood? Folding and cutting paper must be among the most popular ones. Clever children will always search for something new, even when they play games like cutting paper. Now, Carol, a smart girl, asks her brother Mike to solve a puzzle. However, as always, Mike cannot find the solution, therefore he turns to you for help.Carol's puzzle is simple to state. She folds the paper in a certain manner and then uses a knife to cut through the folded paper. What Mike needs to do is to tell how many pieces the folded paper will turn into after it is cut. To eliminate the ambiguity, we can coordinate the paper as [0, 1] * [0, 1], with the coordinates of lower left corner (0, 0). A fold is denoted by two points (x1, y1) and (x2, y2) on the folding line, with which, the direction of the line is determined by from (x1, y1) to (x2, y2). Carol will always fold the paper from left to right relative to the directed line given (see Figure1). The cut is determined by the two points on the cut line. Please note that the points given to determine the fold or the cut are not necessarily on the paper.
Input
The first line of the input contains one integer t, the number of test cases. Then t cases follow. For each test case, the first line consists of an integer N (0 <= N <= 20), the number of folds, and the following N lines give two points on each fold line as x1, y1, x2, y2. The following line gives two points on the cut line in the same way.Output
For each test case, output one line containing the number of pieces the paper will turn into after the cut.Sample Input
2
1
0 0.5 1 1
0.5 0 0.5 1
1
0 0.5 1 1
0 0.4 1 0.4Sample Output
2
3
Paper Cut _course
20170117Description Still remember those games we played in our childhood? Folding and cutting paper must be among the most popular ones. Clever children will always search for something new, even when they play games like cutting paper. Now, Carol, a smart girl, asks her brother Mike to solve a puzzle. However, as always, Mike cannot find the solution, therefore he turns to you for help. Carol's puzzle is simple to state. She folds the paper in a certain manner and then uses a knife to cut through the folded paper. What Mike needs to do is to tell how many pieces the folded paper will turn into after it is cut. To eliminate the ambiguity, we can coordinate the paper as [0, 1] * [0, 1], with the coordinates of lower left corner (0, 0). A fold is denoted by two points (x1, y1) and (x2, y2) on the folding line, with which, the direction of the line is determined by from (x1, y1) to (x2, y2). Carol will always fold the paper from left to right relative to the directed line given (see Figure1). The cut is determined by the two points on the cut line. Please note that the points given to determine the fold or the cut are not necessarily on the paper. Input The first line of the input contains one integer t, the number of test cases. Then t cases follow. For each test case, the first line consists of an integer N (0 <= N <= 20), the number of folds, and the following N lines give two points on each fold line as x1, y1, x2, y2. The following line gives two points on the cut line in the same way. Output For each test case, output one line containing the number of pieces the paper will turn into after the cut. Sample Input 2 1 0 0.5 1 1 0.5 0 0.5 1 1 0 0.5 1 1 0 0.4 1 0.4 Sample Output 2 3
Paper Cut 彩纸的问题_course
20191004Description Still remember those games we played in our childhood? Folding and cutting paper must be among the most popular ones. Clever children will always search for something new, even when they play games like cutting paper. Now, Carol, a smart girl, asks her brother Mike to solve a puzzle. However, as always, Mike cannot find the solution, therefore he turns to you for help. Carol's puzzle is simple to state. She folds the paper in a certain manner and then uses a knife to cut through the folded paper. What Mike needs to do is to tell how many pieces the folded paper will turn into after it is cut. To eliminate the ambiguity, we can coordinate the paper as [0, 1] * [0, 1], with the coordinates of lower left corner (0, 0). A fold is denoted by two points (x1, y1) and (x2, y2) on the folding line, with which, the direction of the line is determined by from (x1, y1) to (x2, y2). Carol will always fold the paper from left to right relative to the directed line given (see Figure1). The cut is determined by the two points on the cut line. Please note that the points given to determine the fold or the cut are not necessarily on the paper. Input The first line of the input contains one integer t, the number of test cases. Then t cases follow. For each test case, the first line consists of an integer N (0 <= N <= 20), the number of folds, and the following N lines give two points on each fold line as x1, y1, x2, y2. The following line gives two points on the cut line in the same way. Output For each test case, output one line containing the number of pieces the paper will turn into after the cut. Sample Input 2 1 0 0.5 1 1 0.5 0 0.5 1 1 0 0.5 1 1 0 0.4 1 0.4 Sample Output 2 3
剪纸的算法问题 Paper Cut_course
20190909Description Still remember those games we played in our childhood? Folding and cutting paper must be among the most popular ones. Clever children will always search for something new, even when they play games like cutting paper. Now, Carol, a smart girl, asks her brother Mike to solve a puzzle. However, as always, Mike cannot find the solution, therefore he turns to you for help. Carol's puzzle is simple to state. She folds the paper in a certain manner and then uses a knife to cut through the folded paper. What Mike needs to do is to tell how many pieces the folded paper will turn into after it is cut. To eliminate the ambiguity, we can coordinate the paper as [0, 1] * [0, 1], with the coordinates of lower left corner (0, 0). A fold is denoted by two points (x1, y1) and (x2, y2) on the folding line, with which, the direction of the line is determined by from (x1, y1) to (x2, y2). Carol will always fold the paper from left to right relative to the directed line given (see Figure1). The cut is determined by the two points on the cut line. Please note that the points given to determine the fold or the cut are not necessarily on the paper. Input The first line of the input contains one integer t, the number of test cases. Then t cases follow. For each test case, the first line consists of an integer N (0 <= N <= 20), the number of folds, and the following N lines give two points on each fold line as x1, y1, x2, y2. The following line gives two points on the cut line in the same way. Output For each test case, output one line containing the number of pieces the paper will turn into after the cut. Sample Input 2 1 0 0.5 1 1 0.5 0 0.5 1 1 0 0.5 1 1 0 0.4 1 0.4 Sample Output 2 3
Paper Cut，代码实现的方式用C语言_course
20190821Description Still remember those games we played in our childhood? Folding and cutting paper must be among the most popular ones. Clever children will always search for something new, even when they play games like cutting paper. Now, Carol, a smart girl, asks her brother Mike to solve a puzzle. However, as always, Mike cannot find the solution, therefore he turns to you for help. Carol's puzzle is simple to state. She folds the paper in a certain manner and then uses a knife to cut through the folded paper. What Mike needs to do is to tell how many pieces the folded paper will turn into after it is cut. To eliminate the ambiguity, we can coordinate the paper as [0, 1] * [0, 1], with the coordinates of lower left corner (0, 0). A fold is denoted by two points (x1, y1) and (x2, y2) on the folding line, with which, the direction of the line is determined by from (x1, y1) to (x2, y2). Carol will always fold the paper from left to right relative to the directed line given (see Figure1). The cut is determined by the two points on the cut line. Please note that the points given to determine the fold or the cut are not necessarily on the paper. Input The first line of the input contains one integer t, the number of test cases. Then t cases follow. For each test case, the first line consists of an integer N (0 <= N <= 20), the number of folds, and the following N lines give two points on each fold line as x1, y1, x2, y2. The following line gives two points on the cut line in the same way. Output For each test case, output one line containing the number of pieces the paper will turn into after the cut. Sample Input 2 1 0 0.5 1 1 0.5 0 0.5 1 1 0 0.5 1 1 0 0.4 1 0.4 Sample Output 2 3
Paper Cutting _course
20170505ACM managers need business cards to present themselves to their customers and partners. After the cards are printed on a large sheet of paper, they are cut with a special cutting machine. Since the machine operation is very expensive, it is necessary to minimize the number of cuts made. Your task is to find the optimal solution to produce the business cards. There are several limitations you have to comply with. The cards are always printed in a grid structure of exactly a x b cards. The structure size (number of business cards in a single row and column) is fixed and cannot be changed due to a printing software restrictions. The sheet is always rectangular and its size is fixed. The grid must be perpendicular to the sheet edges, i.e., it can be rotated by 90 degrees only. However, you can exchange the meaning of rows and columns and place the cards into any position on the sheet, they can even touch the paper edges. For instance, assume the card size is 3 x 4 cm, and the grid size 1 x 2 cards. The four possible orientations of the grid are depicted in the following figure. The minimum paper size needed for each of them is stated. The cutting machine used to cut the cards is able to make an arbitrary long continuous cut. The cut must run through the whole piece of the paper, it cannot stop in the middle. Only one free piece of paper can be cut at once  you cannot stack pieces of paper onto each other, nor place them beside each other to save cuts. Input Specification The input consists of several test cases. Each of them is specified by six positive integer numbers, A,B,C,D,E,F, on one line separated by a space. The numbers are: A and B are the size of a rectangular grid, 1 <= A,B <= 1 000, C and D are the dimensions of a card in cms, 1 <= C,D <= 1 000, and E and F are the dimensions of a paper sheet in cms, 1 <= E,F <= 1 000 000. The input is terminated by a line containing six zeros. Output Specification For each of the test cases, output a single line. The line should contain the text: "The minimum number of cuts is X.", where X is the minimal number of cuts required. If it is not possible to fit the card grid onto the sheet, output the sentence "The paper is too small." instead. Sample Input 1 2 3 4 9 4 1 2 3 4 8 3 1 2 3 4 5 5 3 3 3 3 10 10 0 0 0 0 0 0 Sample Output The minimum number of cuts is 2. The minimum number of cuts is 1. The paper is too small. The minimum number of cuts is 10.
Paper Cutting Game 的计算_course
20191218Problem Description Lily and Lucy are playing a new paper cutting game. The game uses a rectangular paper that consists of W*H grids.At first,there is only a sheet of W*H paper. In each turn,One player picks up cut one piece of paper and cut it into several pieces of equal rectangular sections,and puts them back. Lily can only cut horizontally and Lucy can only cut vertically,keeping every grids unbroken.The one who can’t cut the paper loses. Now given you a sheet of W*H paper.We know Lily always plays first.We can assume that both player are clever enough to make the right move.Could you help Lily to make sure if she can win the game? Input Input contains multiple cases. Each test case starts with two integerW(1<=N<=1000) ,H(1<=H<=1000) ,says that there is a sheet of W*H paper at firsst. Output For each test case, if Lily can win the game output “Win”,otherwise output “Lose”. Sample Input 1 1 2 2 4 2 6 4 Sample Output Lose Lose Win Lose
Rock, Paper, or Scissors? _course
20170602Problem Description Rock, Paper, Scissors is a two player game, where each player simultaneously chooses one of the three items after counting to three. The game typically lasts a predetermined number of rounds. The player who wins the most rounds wins the game. Given the number of rounds the players will compete, it is your job to determine which player wins after those rounds have been played. The rules for what item wins are as follows: ?Rock always beats Scissors (Rock crushes Scissors) ?Scissors always beat Paper (Scissors cut Paper) ?Paper always beats Rock (Paper covers Rock) Input The first value in the input file will be an integer t (0 < t < 1000) representing the number of test cases in the input file. Following this, on a case by case basis, will be an integer n (0 < n < 100) specifying the number of rounds of Rock, Paper, Scissors played. Next will be n lines, each with either a capital R, P, or S, followed by a space, followed by a capital R, P, or S, followed by a newline. The first letter is Player 1抯 choice; the second letter is Player 2抯 choice. Output For each test case, report the name of the player (Player 1 or Player 2) that wins the game, followed by a newline. If the game ends up in a tie, print TIE. Sample Input 3 2 R P S R 3 P P R S S R 1 P R Sample Output Player 2 TIE Player 1
Cutting trees _course
20170712Problem Description A rooted graph is an indirected graph with every edge attached by some path to a special vertex called the root or the ground. The ground is denoted in the below figures that follow by a dotted line. A bamboo stalk with n segments is a linear graph of n edges with the bottom of the n edges rooted to the ground. A move consists of hacking away one of the segments, and removing that segment and all segments above it no longer connectd to the ground. Two players alternate moves and the last player to move wins. A single bamboo stalk of n segments can be moved into a bamboo stalk of any smaller number of segments from n1 to 0. So a single bamboo stalk of n segments is equivalent to a nim pile of n chips. As you known, the player who moves first can win the the game with only one bamboo stalk. So many people always play the game with several bamboo stalks. One example is as below: Playing a sum of games of bamboo stalks is thus equivalent to playing a nim game that with several piles. A move consisits of selecting a bamboo stalk containg n segments and hacking away one of the segments in the selected bamboo stalk. I think the nim game is easy for you, the smart ACMers. So, today, we play a game named "cutting trees". A "rooted tree" is a graph with a distinguished vertex called the root, with the property that from every vertex there is unique path(that doesn't repeat edges) to the root. Essentially this means there are no cycles. Of course, in the game "cutting trees", there are several trees.Again, a move consisits of selecting a tree and hacking away any segment and removing segment and anything not connected to the ground. The player who cuts the last segment wins the game. Input Standard input will contain multiple test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow. Each case begins with a N(1<=N<=1000), the number of trees in the game.A tree is decribed by a number m, the nodes of the tree and R(0<=R<=m1), the root of the tree. Then m1 lines follow, each line containg two positive integers A,B∈[0,m1], means that there is a edge between A and B. In the game, the first player always moves first. Output Results should be directed to standard output. For each case, if the first player wins, ouput "The first player wins", or else, output "The second player wins",in a single line. Sample Input 1 1 4 0 0 1 1 2 1 3 Sample Output The first player wins
一个圆柱体的摆放计算的问题，求容积，采用数据结构C语言_course
20190114Problem Description Using a sheet of paper and scissors, you can cut out two faces to form a cylinder in the following way: 1. Cut the paper horizontally (parallel to the shorter side) to get two rectangular parts. 2. From the first part, cut out a circle of maximum radius. The circle will form the bottom of the cylinder. 3. Roll the second part up in such a way that it has a perimeter of equal length with the circle's circumference, and attach one end of the roll to the circle. Note that the roll may have some overlapping parts in order to get the required length of the perimeter. Given the dimensions of the sheet of paper, can you calculate the biggest possible volume of a cylinder which can be constructed using the procedure described above? Input The input consists of several test cases. Each test case consists of two numbers w and h (1 ≤ w ≤ h ≤ 100), which indicate the width and height of the sheet of paper. The last test case is followed by a line containing two zeros. Output For each test case, print one line with the biggest possible volume of the cylinder. Round this number to 3 places after the decimal point. Sample Input 10 10 10 50 10 30 0 0 Sample Output 54.247 785.398 412.095
Good Rectangle _course
20170825We need k square pieces cut from a rectangular piece of paper with length a and width b. Here we assume a is greater than b. Obviously, the biggest side length of a square we can get is b, so the length a of the rectangular piece must be greater than k × b. And after k squares got, the rest part of original rectangle should be a rectangular piece with length b and width c = a  b × k. Here we assume b is not less than c, or we will waste too much. To reuse the rest part, we want the rest rectangle is similar to the original rectangle, but it is impossible (can you prove?). To measure how similar is the rest rectangle to the original rectangle, we define best(b) = min {abs( b ÷ ( x  k × b )  x ÷ b )  for x ≥ k × b}. We call b is a good width if best(b) is less than best(d) for any positive d less than b. And if a rectangle with a good width b and a length a which makes abs(b ÷ (a  k × b)  a ÷ b) minimal, it is a good rectangle. We can get the result easily for each good width, a good rectangle can be got. And we sort the good rectangles by its width from small to large. Now given k, can you calculate area of the nth good rectangle? (all variables above is integer) Input There are no more than test cases. Each test case has only one line, containing two integers k and n (0 < k < 1000001, 0 < n < 1000001). Output Output one line for each case, each case need only a number contained one integer S, which indicates the area of the nth good rectangle. S may be very large, so print S MOD 9875321. Sample Input 1 10 2 1 Sample Output 12816 3
Cutting Game _course
20171005Description Urej loves to play various types of dull games. He usually asks other people to play with him. He says that playing those games can show his extraordinary wit. Recently Urej takes a great interest in a new game, and Erif Nezorf becomes the victim. To get away from suffering playing such a dull game, Erif Nezorf requests your help. The game uses a rectangular paper that consists of W*H grids. Two players cut the paper into two pieces of rectangular sections in turn. In each turn the player can cut either horizontally or vertically, keeping every grids unbroken. After N turns the paper will be broken into N+1 pieces, and in the later turn the players can choose any piece to cut. If one player cuts out a piece of paper with a single grid, he wins the game. If these two people are both quite clear, you should write a problem to tell whether the one who cut first can win or not. Input The input contains multiple test cases. Each test case contains only two integers W and H (2 <= W, H <= 200) in one line, which are the width and height of the original paper. Output For each test case, only one line should be printed. If the one who cut first can win the game, print "WIN", otherwise, print "LOSE". Sample Input 2 2 3 2 4 2 Sample Output LOSE LOSE WIN
怎么运用 C 语言的程序，Cylinder_course
20190810Problem Description Using a sheet of paper and scissors, you can cut out two faces to form a cylinder in the following way: 1. Cut the paper horizontally (parallel to the shorter side) to get two rectangular parts. 2. From the first part, cut out a circle of maximum radius. The circle will form the bottom of the cylinder. 3. Roll the second part up in such a way that it has a perimeter of equal length with the circle's circumference, and attach one end of the roll to the circle. Note that the roll may have some overlapping parts in order to get the required length of the perimeter. Given the dimensions of the sheet of paper, can you calculate the biggest possible volume of a cylinder which can be constructed using the procedure described above? Input The input consists of several test cases. Each test case consists of two numbers w and h (1 ≤ w ≤ h ≤ 100), which indicate the width and height of the sheet of paper. The last test case is followed by a line containing two zeros. Output For each test case, print one line with the biggest possible volume of the cylinder. Round this number to 3 places after the decimal point. Sample Input 10 10 10 50 10 30 0 0 Sample Output 54.247 785.398 412.095
Cylinder 用C语言来写_course
20190829Problem Description Using a sheet of paper and scissors, you can cut out two faces to form a cylinder in the following way: 1. Cut the paper horizontally (parallel to the shorter side) to get two rectangular parts. 2. From the first part, cut out a circle of maximum radius. The circle will form the bottom of the cylinder. 3. Roll the second part up in such a way that it has a perimeter of equal length with the circle's circumference, and attach one end of the roll to the circle. Note that the roll may have some overlapping parts in order to get the required length of the perimeter. Given the dimensions of the sheet of paper, can you calculate the biggest possible volume of a cylinder which can be constructed using the procedure described above? Input The input consists of several test cases. Each test case consists of two numbers w and h (1 ≤ w ≤ h ≤ 100), which indicate the width and height of the sheet of paper. The last test case is followed by a line containing two zeros. Output For each test case, print one line with the biggest possible volume of the cylinder. Round this number to 3 places after the decimal point. Sample Input 10 10 10 50 10 30 0 0 Sample Output 54.247 785.398 412.095
Cylinder 圆柱的问题_course
20190826Problem Description Using a sheet of paper and scissors, you can cut out two faces to form a cylinder in the following way: 1. Cut the paper horizontally (parallel to the shorter side) to get two rectangular parts. 2. From the first part, cut out a circle of maximum radius. The circle will form the bottom of the cylinder. 3. Roll the second part up in such a way that it has a perimeter of equal length with the circle's circumference, and attach one end of the roll to the circle. Note that the roll may have some overlapping parts in order to get the required length of the perimeter. Given the dimensions of the sheet of paper, can you calculate the biggest possible volume of a cylinder which can be constructed using the procedure described above? Input The input consists of several test cases. Each test case consists of two numbers w and h (1 ≤ w ≤ h ≤ 100), which indicate the width and height of the sheet of paper. The last test case is followed by a line containing two zeros. Output For each test case, print one line with the biggest possible volume of the cylinder. Round this number to 3 places after the decimal point. Sample Input 10 10 10 50 10 30 0 0 Sample Output 54.247 785.398 412.095
Cylinder 程序的实现方式_course
20190910Problem Description Using a sheet of paper and scissors, you can cut out two faces to form a cylinder in the following way: 1. Cut the paper horizontally (parallel to the shorter side) to get two rectangular parts. 2. From the first part, cut out a circle of maximum radius. The circle will form the bottom of the cylinder. 3. Roll the second part up in such a way that it has a perimeter of equal length with the circle's circumference, and attach one end of the roll to the circle. Note that the roll may have some overlapping parts in order to get the required length of the perimeter. Given the dimensions of the sheet of paper, can you calculate the biggest possible volume of a cylinder which can be constructed using the procedure described above? Input The input consists of several test cases. Each test case consists of two numbers w and h (1 ≤ w ≤ h ≤ 100), which indicate the width and height of the sheet of paper. The last test case is followed by a line containing two zeros. Output For each test case, print one line with the biggest possible volume of the cylinder. Round this number to 3 places after the decimal point. Sample Input 10 10 10 50 10 30 0 0 Sample Output 54.247 785.398 412.095
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20200609限时秒杀，先到先得！！！ 购买后添加“助手小姐姐”微信，还可有不定期直播活动和老师答疑哦！ 【授课老师】 彭靖田 Google Developer Experts。 曾为 TensorFlow Top 40 的贡献者，著书《深入理解TensorFlow》，是国内第一本深度剖析 Google AI 框架的畅销书。 曾从0到1深入参与了华为 2012 实验室深度学习平台和华为深度学习云服务的设计与研发工作。 【课程会讲哪些知识？】 整个课程以理论加实战为核心，通过从基础原理、代码案例带你手把手入门神经网络。下面是课程的知识概览思维导图。
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20200223[为什么要学习Spring Cloud微服务] SpringCloud作为主流微服务框架，已成为各互联网公司的首选框架，国内外企业占有率持续攀升，是Java工程师的必备技能。就连大名鼎鼎的阿里巴巴dubbo也正式更名为Spring Cloud Alibaba，成为了Spring Cloud 微服务中的一个子模块。Spring Cloud是企业架构转型、个人能力提升、架构师进阶的不二选择。 【推荐你学习这门课的理由】 1、本课程总计29课时，从微服务是什么、能够做什么开始讲起，绝对的零基础入门 2、课程附带全部26个项目源码，230页高清PDF正版课件 【课程知识梳理】 1、先讲解了什么是单体架构、什么是微服务架构、他们之间有什么区别和联系，各自有什么优缺点。 2、从本质入手，使用最简单的Spring Boot搭建微服务，让你认清微服务是一种思想和解决问题的手段，而不是新兴技术。 3、讲解Spring Boot 与Spring Cloud 微服务架构之间的联系，原生的RestTemplate工具，以及Actuator监控端点的使用。 4、带着微服务所带来的各种优缺点，为大家引入服务发现与注册的概念和原理，从而引入我们的第一个注册中心服务Eureka。 5、引入负载均衡的理念，区分什么是服务端负载均衡，什么是客户端负载均衡，进而引入Ribbon负载均衡组件的详细使用。 6、为了解决微服务之间复杂的调用，降低代码的复杂度，我们引入了Feign声明式客户端，让你几行代码搞定服务的远程调用。 7、最后为大家介绍了整个微服务体系应该包含什么，学习路线是什么，应该学习什么。 【学习方法】 每一节课程均有代码，最好的方式是静下心来，用一天的时间，或者两个半天时间来学习。 一边听我的讲解，一边使用我提供的项目代码进行观察和运行。 只要你能跟住我的节奏，你就可以搞定微服务。
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