如何将list《map》（String ，object）转化成。list！！

Question

[{pjcj=161.0, CESHIRIQI=2011, SUOSHUQUYU=通州区}, {pjcj=166.0, CESHIRIQI=2012, SUOSHUQUYU=通州区}, {pjcj=159.5, CESHIRIQI=2014, SUOSHUQUYU=通州区}, {pjcj=180.0, CESHIRIQI=2015, SUOSHUQUYU=通州区}, {pjcj=140.5, CESHIRIQI=2016, SUOSHUQUYU=东城区}, {pjcj=167.94, CESHIRIQI=2016, SUOSHUQUYU=密云区}, {pjcj=169.45, CESHIRIQI=2016, SUOSHUQUYU=房山区}, {pjcj=161.91, CESHIRIQI=2016, SUOSHUQUYU=昌平区}, {pjcj=166.75, CESHIRIQI=2017, SUOSHUQUYU=亦庄经济开发区}, {pjcj=162.63, CESHIRIQI=2017, SUOSHUQUYU=延庆}, {pjcj=163.21, CESHIRIQI=2017, SUOSHUQUYU=怀柔区}, {pjcj=166.43, CESHIRIQI=2017, SUOSHUQUYU=石景山区}, {pjcj=164.08, CESHIRIQI=2017, SUOSHUQUYU=通州区}, {pjcj=167.53, CESHIRIQI=2017, SUOSHUQUYU=门头沟区}, {pjcj=164.37, CESHIRIQI=2017, SUOSHUQUYU=顺义区}, {pjcj=166.58, CESHIRIQI=2017, SUOSHUQUYU=首都职工体质促进中心}]
这是得到的数据，如何才能变成
series: [{
name: '通州',
data: [161.0, 166.0, 159.5, 180.0]
},
类似于这种格式，一个地区，对应一个集合。

Answer 1

##这个可以用alibaba的fastjson来做，把字符串转化成类对象，然后做归总
##下面提供个不用fastjson的比较死的方法来做（不是很好），但也可用

import com.alibaba.fastjson.JSON;

import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;


public class Test {
   public static void  main(String arg[]){
       List<Map<String,Object>>  mapList=new ArrayList<>();
       Map<String,Object>  map1=new HashMap<>();
       map1.put("pjcj",161.1);
       map1.put("CESHIRIQI",2014);
       map1.put("SUOSHUQUYU","通州区");
       Map<String,Object>  map2=new HashMap<>();
       map2.put("pjcj",162.0);
       map2.put("CESHIRIQI",2015);
       map2.put("SUOSHUQUYU","通州区");
       Map<String,Object>  map3=new HashMap<>();
       map3.put("pjcj",151.0);
       map3.put("CESHIRIQI",2014);
       map3.put("SUOSHUQUYU","房山区");
       Map<String,Object>  map4=new HashMap<>();
       map4.put("pjcj",152.0);
       map4.put("CESHIRIQI",2014);
       map4.put("SUOSHUQUYU","房山区");
       mapList.add(map1);
       mapList.add(map2);
       mapList.add(map3);
       mapList.add(map4);

       Map<String,List<Double>>  areaData=new HashMap<>();

       for (Map<String,Object> map:mapList) {
         String areaName=(String) map.get("SUOSHUQUYU");
         double data=(double)map.get("pjcj");
         if(areaData.get(areaName)!=null){
             List<Double> datas=areaData.get(areaName);
             datas.add(data);
         }else{
             List<Double> datass=new ArrayList<Double>();
             datass.add(data);
             areaData.put(areaName,datass);
         }

       }
       List<Map<String,Object>> series=new ArrayList<>();
       for (String key: areaData.keySet()) {
           Map<String,Object> map=new HashMap<>();
           map.put("name",key);
           map.put("data",areaData.get(key));
           series.add(map);
       }

       String  json=JSON.toJSONString(series);
       System.out.print(json);
   }
}

结果：[{"name":"房山区","data":[151,152]},{"name":"通州区","data":[161.1,162]}]

注意依赖：

 <dependency>
             <groupId>com.alibaba</groupId>
             <artifactId>fastjson</artifactId>
             <version>1.2.8</version>
         </dependency>