data("id",id) 无法获取表格中<tr>所绑定的id值

Question

                                //绑定id值到tr
                                    var tr="<tr>";  
                                    tr+="<td>";
                                    tr+="<input type='checkbox' value='"+id+"' name='checkbox'/>";
                                    tr+="</td>";
                                    tr+="<td class='td_dep'>"+info_type+"</td>";
                                    tr+="<td class='td_dep'>"+type+"</td>";
                                    tr+="<td class='td_dep'>"+release1+"</td>";
                                    tr+="<td class='td_dep'>"+effective_s+"到"+effective_o+"</td>";
                                    tr+="<td class='td_dep'>"+compete+"</td>";
                                    tr+="<td class='td_dep'>"+region+"</td>";
                                    tr+="<td class='td_dep'>"+product+"</td>";
                                    tr+="<td class='td_dep'>"+source+"</td>";
                                    tr+="</tr>";    
                              var $tr=$(tr);
                              $tr.data("id",id);
                              console.log($tr.data("id"));


                                //获取从tr中获取id值
                                $("#table_content").on("click",".td_dep",function(){

                                //获取绑定 的ID值
                                var $tr=$(this).parent();
                                var id=$tr.data("id");
                                console.log(id);

                                各位大神，为什么获取id值总是提示undifine,需要怎么解决呢

Answer 1

value='"+id+"' 你要不试试** id='"+id+"' **