LinkedHashMap排序LinkedHashMap排序

Question

LinkedHashMap value为float值，如何实现排序

Answer 1

LinkedHashMap<String, Float> map = new LinkedHashMap<>();
        //先转成ArrayList集合
        ArrayList<Entry<String, Float>> list = 
                new ArrayList<Map.Entry<String, Float>>(map.entrySet());
        //从小到大排序（从大到小将o1与o2交换即可）
        Collections.sort(list, new Comparator<Map.Entry<String, Float>>() {

            @Override
            public int compare(Entry<String, Float> o1, Entry<String, Float> o2) {
                return ((o1.getValue() - o2.getValue() == 0) ? 
                        0: (o1.getValue() - o2.getValue() > 0) ? 1: -1);
            }

        });
        //新建一个LinkedHashMap，把排序后的List放入
        LinkedHashMap<String, Float> map2 = new LinkedHashMap<>();
        for (Map.Entry<String, Float> entry : list) {
            map2.put(entry.getKey(), entry.getValue());
        }
        //遍历输出
        for (Map.Entry<String, Float> entry : map2.entrySet()) {
            System.out.println(entry.getKey() + ":" + entry.getValue());
        }

    }

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