java:我使用了idea的进行web项目部署的时候遇到发布失败

报错:
HTTP Status [404] – [Not Found]

Type Status Report

Description The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.
Apache Tomcat/9.0.0.M21

web.xml代码:

 <!DOCTYPE web-app PUBLIC
 "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
 "http://java.sun.com/dtd/web-app_2_3.dtd" >

<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
         version="3.1">

  <display-name>lanneret</display-name>
  <!-- 首页 -->
  <welcome-file-list>
    <welcome-file>index</welcome-file>
  </welcome-file-list>

  <!-- 配置Spring上下文监听器 -->
  <listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
  </listener>

  <!--把applicationContext.xml加入到配置文件中-->
  <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath*:applicationContext.xml</param-value>
  </context-param>

  <!-- Spring MVC 核心控制器 DispatcherServlet 配置 -->
  <servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
      <!--配置dispatcher.xml作为mvc的配置文件-->
      <param-name>contextConfigLocation</param-name>
      <param-value>classpath:dispatcher-servlet.xml</param-value>
    </init-param>
    <!--<load-on-startup>1</load-on-startup>-->
  </servlet>
  <servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>
</web-app>

dispatcher-servlet.xml代码:

 <?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:mvc="http://www.springframework.org/schema/mvc"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">

    <context:component-scan base-package="com.bean.lanneret.controller"/>

    <context:annotation-config/>

    <mvc:annotation-driven/>


    <!--处理静态资源-->
    <mvc:resources mapping="/resource/**" location="/resource/"/>



    <bean id="defaultViewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">

        <property name="prefix" value="/WEB-INF/jsp/page/"/><!--设置JSP文件的目录位置-->
        <property name="suffix" value=".jsp"/>
        <property name="exposeContextBeansAsAttributes" value="true"/>
    </bean>


</beans>

applicationContext.xml代码:

 <?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
    <context:component-scan base-package="com.bean.lanneret"/>
</beans>

2个回答

楼主解决了吗?我也遇到了这个问题

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