如何讲一个Hibernate框架的Web项目改写成Mybtis的项目,求大神指点,急求急求!!

如何讲一个Hibernate框架的Web项目改写成Mybtis的项目,求大神指点,急求急求!!

1个回答

小一点的项目还好改,大的项目不好改的。

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Linux挂载存储服务器失败rn存储服务器已经映射到主机,Linux可以发现,并且登录.rn[root@master /]# iscsiadm -m session -o show rntcp: [17] 10.1.1.2:3260,3 iqn.1986-03.com.ibm:2145.cunchu02.node1 (non-flash)rntcp: [18] 10.1.1.21:3260,3 iqn.1986-03.com.ibm:2145.cunchu01.node2 (non-flash)rntcp: [19] 10.1.1.1:3260,3 iqn.1986-03.com.ibm:2145.cunchu01.node1 (non-flash)rn使用的是multipath多路径,配置如下rnblacklist rn devnode "^sda"rnrndefaults rn user_friendly_names yesrn path_grouping_policy multibusrn failback immediatern no_path_retry failrnrn可是在fdisk和partitions中没有发现,我不知道哪里出现错误了rnrn[root@master /]# cat /proc/partitions rnmajor minor #blocks namernrn 8 0 1169920000 sdarn 8 1 204800 sda1rn 8 2 1048576 sda2rn 8 3 1168664576 sda3rn 253 0 52428800 dm-0rn 253 1 4194304 dm-1rn 253 2 1112039424 dm-2rn 7 0 2880 loop0rn 7 1 488281 loop1rn 253 3 204800 dm-3rn[root@master /]# fdisk -lrnWARNING: fdisk GPT support is currently new, and therefore in an experimental phase. Use at your own discretion.rnrnDisk /dev/sda: 1198.0 GB, 1197998080000 bytes, 2339840000 sectorsrnUnits = sectors of 1 * 512 = 512 bytesrnSector size (logical/physical): 512 bytes / 512 bytesrnI/O size (minimum/optimal): 262144 bytes / 262144 bytesrnDisk label type: gptrnDisk identifier: 795E086A-1F39-4BD1-B589-FB71E3F07825rnrnrn# Start End Size Type Namern 1 2048 411647 200M EFI System EFI System Partitionrn 2 411648 2508799 1G Microsoft basic rn 3 2508800 2339837951 1.1T Linux LVM rnrnDisk /dev/mapper/cl-root: 53.7 GB, 53687091200 bytes, 104857600 sectorsrnUnits = sectors of 1 * 512 = 512 bytesrnSector size (logical/physical): 512 bytes / 512 bytesrnI/O size (minimum/optimal): 262144 bytes / 262144 bytesrnrnrnDisk /dev/mapper/cl-swap: 4294 MB, 4294967296 bytes, 8388608 sectorsrnUnits = sectors of 1 * 512 = 512 bytesrnSector size (logical/physical): 512 bytes / 512 bytesrnI/O size (minimum/optimal): 262144 bytes / 262144 bytesrnrnrnDisk /dev/mapper/cl-home: 1138.7 GB, 1138728370176 bytes, 2224078848 sectorsrnUnits = sectors of 1 * 512 = 512 bytesrnSector size (logical/physical): 512 bytes / 512 bytesrnI/O size (minimum/optimal): 262144 bytes / 262144 bytesrnrnYou must set cylinders.rnYou can do this from the extra functions menu.rnrnDisk /dev/loop0: 2 MB, 2949120 bytes, 5760 sectorsrnUnits = sectors of 1 * 512 = 512 bytesrnSector size (logical/physical): 512 bytes / 512 bytesrnI/O size (minimum/optimal): 512 bytes / 512 bytesrnDisk label type: dosrnDisk identifier: 0x00000000rnrn Device Boot Start End Blocks Id SystemrnrnDisk /dev/loop1: 499 MB, 499999744 bytes, 976562 sectorsrnUnits = sectors of 1 * 512 = 512 bytesrnSector size (logical/physical): 512 bytes / 512 bytesrnI/O size (minimum/optimal): 512 bytes / 512 bytesrnrnrnDisk /dev/mapper/vg1-data1: 209 MB, 209715200 bytes, 409600 sectorsrnUnits = sectors of 1 * 512 = 512 bytesrnSector size (logical/physical): 512 bytes / 512 bytesrnI/O size (minimum/optimal): 512 bytes / 512 bytesrnrnrnrn
急!!!!求大神帮忙
生产机上跑的好好地一个项目,突然之不能登录了,检查代码发现是卡在接口那,不执行也不返回,一直卡着,求各位大神帮忙到底是怎么回事! 在线等。。。。。。rnrn以下是代码‘ action 层 rnprivate ChannelAuthorityService channelAuthorityService;rnrn public ChannelAuthorityService getChannelAuthorityService() rn return channelAuthorityService;rn rnrn public void setChannelAuthorityService(rn ChannelAuthorityService channelAuthorityService) rn this.channelAuthorityService = channelAuthorityService;rn rnrn调用的接口:rnList listt = channelAuthorityService.selectChannelAuthority();rnrnrnrn配置文件:rnrnrnrn rn rn rn rn rn rn rn rnrnweb.xml rnrnrn org.springframework.web.context.ContextLoaderListenerrn rnrn rn contextConfigLocationrn /WEB-INF/applicationContext*.xml,classpath*:applicationContext*.xmlrn rnrnrn接口是通过spring工厂管理的 xml注入,lazy-init = falsernrnrnrnrn
informatica 急求大神
informatica 8.1.1 aix环境,每周都自动重启,今天重启之后控制服务正常,单repository 连不上数据库,报错为database driver error function name logon ORA-00000,服务在今天自动重启时间之前都是好用的,网上也看了很多方法都不好使,急求大神
求大神!!!急!
field: "可执行操作", template:function(item)rn if (item.CHECKSTATE == 0) //未提交 根据文档审核状态显示用户可进行的操作rn rn return str = "编辑 查看 删除";rn rn else if (item.CHECKSTATE == 1)//审批中rn rn return str = "查询";rn rn else if (item.CHECKSTATE == 2)//审批通过rn rn return str = "查看";rn rn else if (item.CHECKSTATE == 3)//未通过rn rn return str = "编辑 查看 ";rn rn else if (item.CHECKSTATE == null)//无状态rn rn return str = " ";rn rn请问根据这个怎么给它跳转页面?就是点查看可以跳转到其他页面?谢谢了!!!
求大神解决问题!急!
[img=https://img-bbs.csdn.net/upload/201709/18/1505696376_680289.png][/img]rnrn比如:我在总公司的网页上点击《所有订单》,则会调取总公司数据库里的“公司名” 表,然后根据这些公司名字再去调取各个子公司下的各自数据库里的“订单表“,然后全部展示在总公司页面上,如果我在总公司页面上筛选其中一个公司,那么则会去调取这个公司的订单表,展示在总公司页面上rnrnrn或者说有没有更简单的方法?rnrnrn各位大神请支招 谢谢
急 求大神。。。
1. 设计一个模式匹配算法,要求:rn【基本要求】rn1) 模式串中支持通配符?和*,其中,表示任意字符, *代表0个或多个任意字符。rn2) 模式串中可以多次出现通配符?和*。rn3) 输出模式串在主串中出现的所有位置rn【提示】rn采用模式匹配算法进行改进,设主串为S,模式串为P,P中含有通配符?和*。rn1) 若模式串当前字符为?, 则直接比较主串和模式串的下一个字符。rn2) 若模式串当前字符为*, 则在主串中直接查找第一个与模式串*后的下一个字符匹配的字符,继续进行后面的比较rn
求大神指教!急!
[align=left]我想做个闹钟提醒,在EssayActivity中设置时间,启动服务,获取系统时间,两者相等闹钟响。但是service中一直有错(异常)Calling a method in the system process without a qualified user: android.app.ContextImpl.sendBroadcast:1140 android.content.ContextWrapper.sendBroadcast:345 com.android.settings.batterywarning.ReadCodeTask.sendWarningMessage:59 com.android.settings.batterywarning.ReadCodeTask.run:41 java.util.Timer$TimerImpl.run:284 rn断电调试一直从timer.scheduleAtFixedRate(new TimerTask() 跳到最后 , 0,1000*60);rn线面附上源代码,球大神指教!rnpackage com.example.notepad;rnrnimport java.util.Timer;rnimport java.util.TimerTask;rnrnimport android.app.AlertDialog;rnimport android.app.Service;rnimport android.content.DialogInterface;rnimport android.content.Intent;rnimport android.hardware.SensorManager;rnimport android.media.AudioManager;rnimport android.media.SoundPool;rnimport android.os.IBinder;rnimport android.os.Vibrator;rnimport android.text.format.Time;rnimport android.util.Log;rnrnpublic class EssayService extends Servicern private static final String TAG="EssayService";rn private SensorManager mgr;//传感器rn private Vibrator vibrator;//震动马达rn private SoundPool soundPool;//声音播放对象rn private int streamID =0;//音效流rn private Timer timer;rn public static double year=0;rn public static double month=0;rn public static double day=0;rn public static double hour=0;rn public static double minute=0;rnrnrnrn @Overridern public void onCreate() rn // TODO Auto-generated method stubrn super.onCreate();rn //初始化音效rn soundPool=new SoundPool(10, AudioManager.STREAM_SYSTEM, 5);rn soundPool.load(this, R.raw.kid, 1);rn //获得传感器rn mgr=(SensorManager)getSystemService(SENSOR_SERVICE);rn vibrator=(Vibrator)getSystemService(VIBRATOR_SERVICE);rnrn year=EssayActivity.year;rn month=EssayActivity.month;rn day=EssayActivity.day;rn hour=EssayActivity.hour;rn minute=EssayActivity.minute;rnrn rnrnrnrnrn @Overridern public void onDestroy() rn // TODO Auto-generated method stubrn //Service结束时停止音效播放rn if(streamID!=0)rn soundPool.stop(streamID);rn rn if(timer!=null)rn timer.cancel();rn rn super.onDestroy();rn rnrnrnrnrn @Overridern public int onStartCommand(Intent intent, int flags, int startId) rn // TODO Auto-generated method stubrn Log.i(TAG, "服务启动");rn //启动服务rn if(timer!=null)rn timer.cancel();rn rn timer=new Timer();rn timer.scheduleAtFixedRate(new TimerTask() rnrn @Overridern public void run() rn// TODO Auto-generated method stubrnrn//获取当前系统同时间rn Time t=new Time();rn t.setToNow();rn double tYear=t.year;rn double tMonth=t.month;rn double tDay=t.monthDay;rn double tHour=t.hour;rn double tMinute=t.minute;rnif(year==tYear&&month==tMonth&&day==tDayrn &&hour==tHour&&minute==tMinute)rn//振动,播放声音rnvibrator.vibrate(1000);rnif(streamID==0)rnstreamID=soundPool.play(1, 1, 1, 0, -1, 1);rn rnnew AlertDialog.Builder(EssayService.this)rn.setTitle("是否取消?")rn.setNegativeButton("是", new DialogInterface.OnClickListener() rnrn @Overridern public void onClick(DialogInterface dialog, int which) rn// TODO Auto-generated method stubrn if(timer!=null)rn timer.cancel();rn timer.purge();rn rnrn)rn.setNegativeButton("取消", new DialogInterface.OnClickListener() rnrn@Overridernpublic void onClick(DialogInterface dialog, int which) rn// TODO Auto-generated method stubrnrnrn)rn.show();rnrnrn, 0,1000*60);rnreturn super.onStartCommand(intent, flags, startId);rnrnrnrnrnrn @Overridernpublic IBinder onBind(Intent intent) rn// TODO Auto-generated method stubrnreturn null;rnrnrnrn下面是从EssayActivity转到service的代码rncase R.id.btnClock:rn LayoutInflater inflater=getLayoutInflater();rn final View layout=inflater.inflate(R.layout.timeset, rn(ViewGroup)findViewById(R.id.dialog));rnfinal EditText passText=new EditText(this);rnpassText.setInputType(InputType.TYPE_CLASS_TEXT);rnnew AlertDialog.Builder(EssayActivity.this)rn.setTitle("请输入提示日期:")rn.setView(layout)rn.setPositiveButton("确定", new DialogInterface.OnClickListener() rn rn@Overridernpublic void onClick(DialogInterface dialog, int which) rnLayoutInflater factory = LayoutInflater.from(log.this);rnfinal View textEntryView = factory.inflate(R.layout.dialog, null);rnrn rnEditText editYear=(EditText)layout.findViewById(R.id.editYear);rnEditText editMonth=(EditText)layout.findViewById(R.id.editMonth);rnEditText editDay=(EditText)layout.findViewById(R.id.editDay);rnEditText editHour=(EditText)layout.findViewById(R.id.editHour);rnEditText editMinite=(EditText)layout.findViewById(R.id.editMinite);rntryrnyear=Double.parseDouble(editYear.getText().toString());rnmonth=Double.parseDouble(editMonth.getText().toString());rnday=Double.parseDouble(editDay.getText().toString());rnhour=Double.parseDouble(editHour.getText().toString());rnminute=Double.parseDouble(editMinite.getText().toString());rncatch(Exception e)rne.printStackTrace();rn[align=left]rnsaveEssayPassword();rnIntent intent=new Intent(EssayActivity.this,EssayService.class);rnstartService(intent);rn rnrn)rn.setNegativeButton("取消",[/align] new DialogInterface.OnClickListener()
求大神帮忙!急!
用C++语言编写程序,判断一个点与三角形的关系,是在三角形内还是在三角形上或是在三角形外。
大神,急求啊
1. 给出一个Document类,从Document派生出Book类,增加PageCount变量。在主函数中进行测试,创建Book类对象并进行初始化,输出书名和页数。rn2. 设计一个单继承的类层次程序,利用Person类派生出Student类,增加属性xh(学号),Person类中至少有姓名、年龄等数据成员,成员函数中构造函数对其初始化,析构函数释放相应存储单元,输出函数输出其数据成员的值,其它成员函数根据需要添加,在主函数中进行测试。rn
急求大神帮忙
大家可以看到在数据库中有这样的数据,rn[img=https://img-bbs.csdn.net/upload/201310/08/1381190529_706125.jpg][/img]rn我想做成想这样的格式rn[img=https://img-bbs.csdn.net/upload/201310/08/1381190543_904606.jpg][/img]rn但是我用了datalist控件,它是在表中一行一行的读,我现在想要五行一读,根据rig number, date 来分组读取数据,请问怎么写
急~~大神求指导
我现在在做一个注册登录,用vc#窗体编程,要求用户注册后信息写入txt,修改密码时需要匹配txt中的部分信息,如果匹配成功,可以修改密码;为什么匹配非汉字行的时候可以,匹配汉字行的时候不可以;而且有时候能匹配成功,有时候匹配不成功~~
急求WEB大神
页面上有两个表格,要实现点击上面表格的任意一行下面表格显示与之相关的信息,怎么实现求大神!!!!
急求!大神帮忙
公司让我开发一个福昕PDF编辑器,我是初学者,该怎么办呀?跪谢大神帮忙!!![img=https://forum.csdn.net/PointForum/ui/scripts/csdn/Plugin/003/onion/33.gif][/img]
求大神,急急急
在jquery中怎么样隐藏标签内容
求大神指教。。。急
一般这个错误是什么错误:rnrn [img=https://img-bbs.csdn.net/upload/201504/17/1429254541_87860.png][/img]rnrn求指教。。。rn谢谢。。。
急求大神
在编辑网页时,如果想使vrml文件的场景的节点沿着x方向行走那么可以利用如下节点M.Nodes("x1fangxiang").Fields("translation").x+=150来实现,那么如果想绕沿着与x轴成30度的方向行走,怎么控制和实现呢
急求大神分析程序
该程序是为了实现查字典功能,英汉,汉英翻译。新增单词之后不能查找到,提示段错误。弄了好几天了还是不知道哪里有错误!rnapp.crnrn#includern#includern#include"module.h"rn#include"app.h"rnrnvoid function()rnrn char input[100];rn vocab * wp1;rn vocab * wp2;rn display();rn printf("If you want to translate words,please input 1\n");rn printf("If you want to add the new words,please input 2\n");rn printf("If you want to exit,please input 0\n");rn while(1)rn rn printf("\nplease input your chioce:");rn int choice;rn scanf("%d",&choice);rn switch(choice)rn rn case 0 : exit(1);rn rn case 1 : printf("please input a word :");rn scanf("%s",input);rn wp1 = import();rn rn while(!compare(wp1->word,input))rn rn if(wp1->next != NULL)rn wp1 = wp1->next;rn else break;rn rn rn if(wp1->next != NULL)rn rn outPut(wp1);rn rn rn elsern rn wp2 = importnew();rn while(!compare(wp2->word,input))rn rn if(wp2->next != NULL)rn wp2 = wp2->next;rn else break;rn rn rn if(wp2->next != NULL)rn outPut(wp2);rn elsern printf("\nCan't find you word");rn rn break;rn rn case 2 : addnew();rn break;rn rn printf("\n");rn rnrnrnapp.hrnrn#ifndef __APP_H__rn#define __APP_H__rnrnextern void function();rnrnrn#endifrnrnmodule.crnrn#includern#includern#includern#include"module.h"rnrnlexicon import(void)rnrn int i = 0;rn char c1,c2;rn FILE *fp = NULL;rn fp = fopen("dict.txt","r");rn if(fp == NULL)rn rn fprintf(stderr,"Failed to open dict\n");rn exit(1);rn rn rn lexicon head,p1,p2;rn head = NULL;rn p1 = (lexicon)malloc(sizeof(vocab));rn p2 = (lexicon)malloc(sizeof(vocab));rn for(i = 0;;i++)rn rn c1 = fgetc(fp);rn c2 = fgetc(fp);rn if(c1 != '\n')rn p1->word[i] = c2;rn else break;rn rn rn for(i = 1;;i++)rn rn c1 = fgetc(fp);rn if(c1!='\n')rn rn p1->trans[0] = 'T';rn p1->trans[i] = c1;rn rn else break;rn rn head = p1;rn rn dorn p2->next = p1;rn p2 = p1;rn p1 = (lexicon)malloc(sizeof(vocab));rn rn for(i = 0; ;i++)rn rn c1 = fgetc(fp);rn if(c1 != '\n')rn p1->word[i] = c1;rn else rn break;rn rn for(i = 0; ;i++)rn rn c1 = fgetc(fp);rn if(c1 != '\n')rn p1->trans[i] = c1;rn else rn break;rn rn while((c1 = fgetc(fp)) != EOF);rn p2->next = NULL;rn fclose(fp);rn return(head);rnrnrnint compare(char *str1,char *str2)rnrnrn if(strcmp(str2,str1) == 0)rn rn return 1;rn rn else rn rn return 0;rn rnrnrnint outPut(lexicon wp)rnrn int i = 0;rn for(i = 0;i <= 50;i++)rn rn printf("%c",wp->trans[i]);rn rn return 0;rnrnrnvoid addnew()rnrn char c;rn char s1[100],s2[100]; rn FILE *fp = NULL;rn fp = fopen("newfile.txt","a+");rn if(fp == NULL)rn rn fprintf(stderr,"failed to open newfile\n");rn exit(1);rn rn scanf("%s",s1);rn fprintf(fp,"%s",s1);rn fprintf(fp,"\n");rn fflush(fp);rn while( (c = getchar() ) =='\n' )rn rn rn rn fgets(s2,99,stdin);rn fprintf(fp,"T");rn fprintf(fp,"%s",s2);rn fclose(fp);rnrnrnlexicon importnew(void)rnrn int i = 0;rn char c1,c2;rn FILE *fp = NULL;rn fp = fopen("newfile.txt","r");rn if(fp == NULL)rn rn fprintf(stderr,"Failed to open newfile\n");rn exit(1);rn rn rn lexicon head,p1,p2;rn head = NULL;rn p1 = (lexicon)malloc(sizeof(vocab));rn p2 = (lexicon)malloc(sizeof(vocab));rn rn for(i = 0;;i++)rn rn c1 = fgetc(fp);rn c2 = fgetc(fp);rn if(c1 != '\n')rn p1->word[i] = c2;rn else break;rn rn rn for(i = 1;;i++)rn rn c1 = fgetc(fp);rn if(c1!='\n')rn rn p1->trans[0] = 'T';rn p1->trans[i] = c1;rn rn else break;rn rn head = p1;rnrn dorn p2->next = p1;rn p2 = p1;rn p1 = (lexicon)malloc(sizeof(vocab));rn for(i = 0; ;i++)rn rn c1 = fgetc(fp);rn if(c1 != '\n')rn p1->word[i] = c1;rn else break;rn rn for(i = 0; ;i++)rn rn c1 = fgetc(fp);rn if(c1 != '\n')rn p1->trans[i] = c1;rn else break;rn rn while((c1 = fgetc(fp)) != EOF);rn p2->next = NULL;rn fclose(fp);rn return(head);rnrnrnvoid display()rnrn printf("\n\t************************************************");rn printf("\n\t* *");rn printf("\n\t* W E *");rn printf("\n\t* *");rn printf("\n\t* Electronic Dictionary *");rn printf("\n\t* *");rn printf("\n\t* *");rn printf("\n\t* *");rn printf("\n\t* 1----Translation *");rn printf("\n\t* 2----Add new words *");rn printf("\n\t* 0----Exit *");rn printf("\n\t* *");rn printf("\n\t************************************************");rn printf("\n\n");rn rn rnrnmodule.hrn#ifndef __MODULE_H__rn#define __MODULE_H__rnrntypedef struct vocabrnrn char word[100];rn char trans[300];rn struct vocab *next;rnvocab,*lexicon;rnrnextern lexicon import(void);rnextern char *getOut(lexicon wp,char wd[]);rnextern int compare(char *, char * );rnextern int outPut(lexicon wp);rnextern void display();rnextern void addnew();rnextern lexicon importnew(void);rnrnrn#endifrnrnmain.crn#includern#include"module.h"rn#include"app.h"rnint main(int argc,char* argv[])rnrn function();rn return 0;rnrnrnrnrnrnrn rn rn
求大神指教...急!!!
先有一个URL带参数的接口地址, 在struts2 中如何请求到这个地址上然后获取,请求返回过来的内容(目前失败返回String,成功返回一个XML文件)
求大神解决问题!!!!!!!!!急
两个表,需要查出卡类型+每种卡的总人数+每种卡的总消费rn[img=https://img-bbs.csdn.net/upload/201403/06/1394093818_843217.png][/img]rn在数据库中可以查出来rn[img=https://img-bbs.csdn.net/upload/201403/06/1394093895_667826.png][/img]rn[img=https://img-bbs.csdn.net/upload/201403/06/1394093904_796940.png][/img]rn但是怎么在dao中传到页面中过去!
急求VB大神
有学过GPS单点定位相关知识的VB大神么?想请教下一个问题
急!!求大神帮忙
网页上有两边的广告位 用js实现当页面缩小的时候不出滚动条 只有当页面小于没有广告位的页面时候才出现滚动条 是横着的那种滚动条 怎么实现
求大神解决 急
求大神解答 如何判定高德地图的事件事件有没有被触发 提交事件的请求 $.ajax({ url: &quot;&quot;, type: &quot;POST&quot;, dataType: &quot;json&quot;, data: obj, success: function (data) { console.log(da...
急!!求大神帮忙!
我想问一下,怎么用android实现颜色填充算法。就是做一个像windows中画板中的颜色填充工具一样的程序。
急求大神解决
编译之后出现以下问题,急求大神解决rnfatal error C1083: Cannot open include file: 'save': No such file or directoryrn执行 cl.exe 时出错.rnrn程序:rn#includern#includern#define MVNum 100rn#define Maxint 32767rnenum booleanFALSE,TRUE;rntypedef char VertexType;rntypedef int Adjmatrix;rntypedef structrnrn VertexType vexs[MVNum];rn Adjmatrix arcs[MVNum][MVNum];rnMGraph;rnrnint D1[MVNum],P1[MVNum];rnint D[MVNum][MVNum],P[MVNum][MVNum];rnrn#include"save"rn#include"djstl"rn#include"floyd"rnrnvoid main()rnrn MGraph *G;rn int m,n,e,v,w,k;rn int xz=1;rn G=(MGraph *)malloc(sizeof(MGraph));rn printf("输入交通图中城市个数和路径数n,e:");rn scanf("%d,%d",&n,&e);rn CreateMGraph(G,n,e);rn while(xz!=0)rn rn printf("*******求城市之间的最短路径*******");rn printf("==================================\n");rn printf("1.求一个城市到所有城市的最短路径\n");rn printf("2.求任意的两个城市之间的最短路径\n");rn printf("==================================\n");rn printf(" 请选择: 1或2,选择0 退出:");rn scanf("%d",&xz);rn if(xz==2)rn rn Floyd(G,n);rn printf("输入源点(或称起点)和终点:v,w:");rn scanf("%d,%d",&v,&w);rn k=P[v][w];rn if(k==0)rn printf("顶点%d到%d无路径!\n",v,w);rn elsern rn printf("从顶点%d到%d的最短路径是:%d",v,w,v);rn while(k!=w)rn rn printf("——>%d",k);rn k=P[k][w];rn rn printf("——>%d",w);rn printf(" 路径长度:%d\n",D[v][w]);rn rn rn elsern if(xz==1)rn rn printf("求单源路径,输入源点v:");rn scanf("%d",&v);rn Dijkstra(G,v,n);rn rn rn printf("结束求最短路径!\n");rnrnrnvoid CreateMGraph(MGraph *G,int n,int e)rnrn int i,j,k,w;rn for(i=1;i<=n;i++)rn G->vexs[i]=(char)i;rn for(i=1;i<=n;i++)rn for(i=1;j<=n;j++)rn G->arcs[i][j]=Maxint; //初始化邻接矩阵rn printf("输入%d条边的i,j及w:\n",e);rn for(k=1;k<=e;k++)rn rn scanf("%d,%d,%d",&i,&j,&w);rn G->arcs[i][j]=w;rn rn printf("交通网络图的存储结构建立完毕!\n"); rnrnrnvoid Dijkstra(MGraph *G,int vl,int n)rnrn int D2[MVNum],P2[MVNum];rn int v,i,w,min;rn enum boolean S[MVNum];rn for(v=1;v<=n;v++)rn rn S[v]=FALSE;rn D2[v]=G->arcs[vl][v];rn if(D2[v]arcs[v][w]arcs[v][w];rn P2[w]=v;rn rn rn printf("路径长度 路径\n");rn for(i=1;i<=n;i++)rn rn printf("%5d",D2[i]);rn printf("%5d",i);rn v=P2[i];rn while(v!=0)rn rn printf("<-&d",v);rn v=P2[v];rn rn printf("\n");rn rnrnrnvoid Floyd(MGraph *G,int n)rnrn int i,j,k,w,v;rn for(i=1;i<=n;i++)rn for(j=1;j<=n;j++)rn rn if(G->arcs[i][j]!=Maxint)rn P[i][j]=j;rn elsern P[i][j]=0;rn D[i][j]=G->arcs[i][j];rn rn for(k=1;k<=n;k++)rn rn for(j=1;j<=n;j++)rn rn if(D[i][k]+D[k][j]
急求大神解决问题
rn var extToCall = jQuery('#telNo').val();rn var bisNo = false;rnrn jQuery.ajax(rn type : "get",rn cache : false,rn async : false,rn dataType:'json',rn data : rn "eventName" : "newCall",rn "callout_telno" : jQuery('#telNo').val(),rn "callin_telno" : LCCParam.IMPI,rn "domain" : LCC.domain,rn "userId" : document.getElementById("UserId").valuern ,rn url : "/dmexif/loan/call.lcc.record.do",rn success : function(data) rn if(data.successFlag == '1')rn bisNo = data.idNo;rn rnrn rn );rn if(bisNo)rn var uriToCall =this.prefix +this.domain + bisNo+extToCall;rn PhoneClient.MakeCall(uriToCall);rn Timer.init();rn return bisNo;rn rn catch(e)rn alert("软电话当前无法使用,请联系管理员!");rn rn return '';rnrnrn做个查询在赋值到domain里抛送出去做判断的一个需求,请问怎么做
求大神帮忙,急
[code=sql]rnINSERT INTO dbo.UserGiftJDCardRelarn ( UserGiftID ,rn CardID ,rn IsActive ,rn CreateTime ,rn DetailIDrn )rn SELECT @UserGiftID ,rn ID ,rn 1 ,rn GETDATE() ,rn DetailIDrn FROM #NoGetJDCardrn WHERE DetailID > 0; rn[/code]rn有事务里有这样一段代码,已经判断了 WHERE DetailID > 0,为什么插入的数据,DetailID字段还有为null的呢
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