能帮我看看问题在哪嘛？谢谢

Question

#include<stdio.h>
int day_of_year(int year,int month,int day);
int main()
{
  int year,month,day;
  while (scanf("%d/%d/%d",&year,&month,&day)!=EOF)
  {
    printf("%d/%d/%d",year,month,day);
  }
  printf("%d",day_of_year(year,month,day));
  return 0;
}
int day_of_year(int year,int month,int day)
{
  int k,leap;
  int tab[2][13]={
    {0,31,28,31,30,31,30,31,31,30,31,30,31},
    {0,31,29,31,30,31,30,31,31,30,31,30,31}
  };
  leap=(year%4==0&&year%100!=0||year%400==0);
    for(k=1;k<month;k++)
      day=day+tab[leap][k];
      return day;
}

Answer 1

应该是获取年月日那里错了，可以使用一个int类型的变量来获取scanf()函数的返回值，以此来判断是否正确从输入获取到了年月日，如果没有则继续循环获取，如果正确获取到了年月日日期，则可以进行下面的计算操作。

修改如下：

#include<stdio.h>
int day_of_year(int year,int month,int day);
int main()
{
  int year,month,day;
  
  int num=scanf("%d/%d/%d",&year,&month,&day); // 从输入按指定格式获取年月日 
  while (num!=3)  // 如果从输入成功获取的数据不是3项，则继续获取年月日 
  {
       num=scanf("%d/%d/%d",&year,&month,&day);
  }
   printf("%d/%d/%d\n",year,month,day);  // 打印正确获取到的年月日日期 
  
  printf("%d",day_of_year(year,month,day));
  
  return 0;
}
int day_of_year(int year,int month,int day)
{
    
  int k,leap;
  int tab[2][13]={
    {0,31,28,31,30,31,30,31,31,30,31,30,31},
    {0,31,29,31,30,31,30,31,31,30,31,30,31}
  };
  
  leap=(year%4==0&&year%100!=0||year%400==0);
    for(k=1;k<month;k++)
      day=day+tab[leap][k];
      return day;
}