extjs5 hibernate实体关联 值怎么引用？

Question

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import static javax.persistence.GenerationType.IDENTITY;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.Table;

/**

• User entity. @author MyEclipse Persistence Tools
  */
  @Entity
  @Table(name = "user", catalog = "thinkdb")
  public class User implements java.io.Serializable {

  // Fields

  private Long id;
  private Depart depart;
  private String userName;

  // Constructors

  /** default constructor */
  public User() {
  }

  /** full constructor */
  public User(Depart depart, String userName) {
  this.depart = depart;
  this.userName = userName;
  }

  // Property accessors
  @Id
  @GeneratedValue(strategy = IDENTITY)
  @Column(name = "id", unique = true, nullable = false)
  public Long getId() {
  return this.id;
  }

  public void setId(Long id) {
  this.id = id;
  }

  @ManyToOne(fetch = FetchType.LAZY)
  @JoinColumn(name = "depart_id")
  public Depart getDepart() {
  return this.depart;
  }

  public void setDepart(Depart depart) {
  this.depart = depart;
  }

  @Column(name = "user_name", length = 50)
  public String getUserName() {
  return this.userName;
  }

  public void setUserName(String userName) {
  this.userName = userName;
  }

}

import java.util.HashSet;
import java.util.Set;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import static javax.persistence.GenerationType.IDENTITY;
import javax.persistence.Id;
import javax.persistence.OneToMany;
import javax.persistence.Table;

/**

• Depart entity. @author MyEclipse Persistence Tools
  */
  @Entity
  @Table(name = "depart", catalog = "thinkdb")
  public class Depart implements java.io.Serializable {

  // Fields

  private Long id;
  private String departName;
  private Set users = new HashSet(0);

  // Constructors

  /** default constructor */
  public Depart() {
  }

  /** full constructor */
  public Depart(String departName, Set users) {
  this.departName = departName;
  this.users = users;
  }

  // Property accessors
  @Id
  @GeneratedValue(strategy = IDENTITY)
  @Column(name = "id", unique = true, nullable = false)
  public Long getId() {
  return this.id;
  }

  public void setId(Long id) {
  this.id = id;
  }

  @Column(name = "depart_name", length = 50)
  public String getDepartName() {
  return this.departName;
  }

  public void setDepartName(String departName) {
  this.departName = departName;
  }

  @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "depart")
  public Set getUsers() {
  return this.users;
  }

  public void setUsers(Set users) {
  this.users = users;
  }

}

EXTJS

//表格

columns:[
{
    text:'用户名',
    width: 80,
    dataIndex:'username'
},
{
    text:'部门名称',
    width: 100,
    dataIndex:'depart.deparName',//这里如何拿到部门名称 model 字段如何配置可以实现  depart.deparName 取值             
}
],

Answer 1

配置dataReader field的mapping属性隐射到子json对象属性去就行了

有用记得采纳：）

http://docs.sencha.com/extjs/4.1.3/#!/api/Ext.data.Field-cfg-mapping

  Ext.define('ModelName', {
            extend: 'Ext.data.Model',
            fields: ["username",
                { "name": "deparName", mapping: "depart.deparName" }//如果还有其他内嵌JSON对象按照这个进行隐射
            ]
        });

                {
    text:'部门名称',
    width: 100,
    dataIndex:'deparName'/////直接配置为model中定义的field名称就行
}