求大佬解答求大佬解答求大佬解答

Question

封装成函数：b = [[11,12,13],[21,22,23],[31,32,33]],打印出包含22的列表？

Answer 1

b = [[11,12,13],[21,22,23],[31,32,33]]

def list_filter(list_x,a):
    for x in list_x:
        if a in x:
            print(x)
            return b

list_filter(b,22)