Eclipse安装了STS插件后Shift+Ctrl+O就失效了 2C

Eclipse安装了STS插件后Shift+Ctrl+O(自动import)就失效了, 也没有快捷键冲突, 原本Eclipse的Shift+Ctrl+O是可以用的, 安了插件就失效了, 无论是4.6, 4.7 安装STS插件后都会失效, 连新下载的STS-Eclipse都不能用Shift+Ctrl+O, 是只有我有这情况, 还是大家都这样?

1个回答

Csdn user default icon
上传中...
上传图片
插入图片
抄袭、复制答案,以达到刷声望分或其他目的的行为,在CSDN问答是严格禁止的,一经发现立刻封号。是时候展现真正的技术了!
其他相关推荐
Eclipse安装了STS插件后Shift+Ctrl+O就失效了
Eclipse安装了STS插件后Shift+Ctrl+O(自动import)就失效了, 也没有快捷键冲突, 原本Eclipse的Shift+Ctrl+O是可以用的, 安了插件就失效了, 无论是4.6, 4.7 安装STS插件后都会失效, 连新下载的STS-Eclipse都不能用Shift+Ctrl+O, 是只有我有这情况, 还是大家都这样?
eclipse中安装sts插件之后maven就不见了
是不是sts插件和maven插件冲突,我用的是eclipse Mars.2版本,自带maven插件
eclipse安装spring插件STS后就打不开了了
eclipse安装spring插件STS(spring tool suite)后就打不开了了,点击eclipse.exe后显示错误弹窗: the eclipse executable launcher was unable to locate its companion shared library ![图片说明](https://img-ask.csdn.net/upload/201808/28/1535461797_90357.png) 但是点击安装好的STS.exe可以打开,它的界面和eclipse几乎一样除了图标和版本介绍的信息 ![图片说明](https://img-ask.csdn.net/upload/201808/28/1535461836_451977.png) ![图片说明](https://img-ask.csdn.net/upload/201808/28/1535461851_359408.png) ![图片说明](https://img-ask.csdn.net/upload/201808/28/1535461863_956594.png) 而且之前eclipse中的项目在STS界面上都能运行,但是这还是让人看得很别扭,怎么才能恢复原来的eclipse界面同时也能继续用STS框架
eclipse安装完对应的sts插件后按alt+/却不能提示属性值
求教各位大佬:我eclipse安装了sts插件,配置spring中的bean标签下的property标签时按alt+/能自动提示name,value等,但进一步name=""时按alt+/却不能自动提示name里的东西。eclipse左下角提示:Content Assist not available at the current location![图片说明](https://img-ask.csdn.net/upload/201711/06/1509944995_205307.png)
关于Eclipse安装STS不成功
离线安装和在线安装都试过了,这是错误信息, 我下的STS是在官网下载的,对应我Eclipse版本的,为什么会安装不了![图片说明](https://img-ask.csdn.net/upload/201706/23/1498189169_952587.png)
eclipse 4.5.2安装STS想用spring boot,过程显示成功却找不到spring boot,求解惑
如题如图,我的是e4.5.2 ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577709816_444690.png) Java版本1.8 ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577709882_329709.png) 一开始是打算在Eclipse Marketplace上下载STS,可是居然找不到 ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577710005_823329.png) 没办法,只能下载资源包,本地安装,看了攻略,我下的是: springsource-tool-suite-3.7.3.RELEASE-e4.5.2-updatesite.zip 然后就Help --> Install New Software,填入自定名字和包位置 --> OK ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577710222_416913.png) 又点击Available Software Site --> 去掉所有http的打勾项,只留下sts(jar)--> OK ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577710536_847507.png) 主选项页面只勾选IDE结尾的 ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577710696_543382.png) 而后一路next ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577710797_896059.png) ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577710807_458473.png) ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577710823_769628.png) ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577710836_143795.png) ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577710875_962257.png) 发现File --> New --> Other找不到spring和spring boot选项 ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577710975_99435.png) preference里头也没有spring和spring boot选项 ![图片说明](https://img-ask.csdn.net/upload/201912/30/1577711049_522090.png) 该怎么做,求解
求助,各位大神,eclipse的spring插件和maven插件的冲突
请教各位一个问题,我的eclipse版本是Mars4.5.2的,这个软件是自带maven插件,但是我安装sts插件后,自带的maven项目插件不见了,安装sts后,重启eclipse,在首页中是看到了spring IDE插件,但是preference中没有maven了,spring也没有,sts也没有安装成功,反而maven也没有了,怎么办才好呢?我后来重新下载eclipse4.5.2重新解压,还是这个样子弄了两天了,求助哪位好心人能解决这种问题啊
STS 或 myeclipse ctrl+shift+f 代码格式化宽度设置在哪?
STS 或 myeclipse ctrl+shift+f 代码格式化宽度设置在哪?
eclipse 安装sts在preference里看不到spring选项
用eclipse mar2安装了springsource tools suite的4.5.2的版本,显示安装完成,重启eclipse后也显示了SpringIDE,但是在preference里找不到Spring选项,而且在编辑spring配置文件时也没有提示
eclipse-sts从svn检出项目时报错如下
![图片说明](https://img-ask.csdn.net/upload/201712/25/1514210122_85562.png) 首先确定不是权限问题,我本地安装了ecilpse和eclipse-sts两个版本软件。同一个svn在ecilpse可以检出,但在eclipse-sts就报错 ![图片说明](https://img-ask.csdn.net/upload/201712/25/1514213277_1509.png) 然后我卸载了svn,然后选择安装svn时,sts提示没有连接
eclipse sts插件创建spring start project springboot项目报错
初学springboot框架,用sts插件搭建了一个 springboot 项目测试一下是否成功。 直接执行main方法说找不到或无法加载主类,当然我的Application类都是自动生成的,注解都有,这个都没问题,但是就是说找不到或无法加载主类。 然后我用maven build启动,报了如下错: [INFO] Scanning for projects... [INFO] [INFO] ------------------------------------------------------------------------ [INFO] Building spring-boot-sample 0.0.1-SNAPSHOT [INFO] ------------------------------------------------------------------------ [INFO] [INFO] >>> spring-boot-maven-plugin:1.5.3.RELEASE:run (default-cli) > test-compile @ spring-boot-sample >>> [INFO] [INFO] --- maven-resources-plugin:2.6:resources (default-resources) @ spring-boot-sample --- [INFO] Using 'UTF-8' encoding to copy filtered resources. [INFO] Copying 1 resource [INFO] Copying 1 resource [INFO] [INFO] --- maven-compiler-plugin:3.1:compile (default-compile) @ spring-boot-sample --- [INFO] Changes detected - recompiling the module! [INFO] Compiling 2 source files to E:\Java learn\All workspacce\dev_springboot\spring-boot-sample\target\classes [INFO] ------------------------------------------------------------- [ERROR] COMPILATION ERROR : [INFO] ------------------------------------------------------------- [ERROR] 读取E:\Java learn\Maven\apache-maven\org\springframework\boot\spring-boot-autoconfigure\1.5.3.RELEASE\spring-boot-autoconfigure-1.5.3.RELEASE.jar时出错; error in opening zip file [ERROR] 读取E:\Java learn\Maven\apache-maven\org\springframework\boot\spring-boot-autoconfigure\1.5.3.RELEASE\spring-boot-autoconfigure-1.5.3.RELEASE.jar时出错; cannot read zip file [ERROR] /E:/Java learn/All workspacce/dev_springboot/spring-boot-sample/src/main/java/com/example/simple/SpringBootSampleApplication.java:[4,46] 程序包org.springframework.boot.autoconfigure不存在 [ERROR] /E:/Java learn/All workspacce/dev_springboot/spring-boot-sample/src/main/java/com/example/simple/SpringBootSampleApplication.java:[6,2] 找不到符号 符号: 类 SpringBootApplication [INFO] 4 errors [INFO] ------------------------------------------------------------- [INFO] ------------------------------------------------------------------------ [INFO] BUILD FAILURE [INFO] ------------------------------------------------------------------------ [INFO] Total time: 3.632 s [INFO] Finished at: 2017-05-07T22:06:15+08:00 [INFO] Final Memory: 22M/191M [INFO] ------------------------------------------------------------------------ [WARNING] The requested profile "pom.xml" could not be activated because it does not exist. [ERROR] Failed to execute goal org.apache.maven.plugins:maven-compiler-plugin:3.1:compile (default-compile) on project spring-boot-sample: Compilation failure: Compilation failure: [ERROR] 读取E:\Java learn\Maven\apache-maven\org\springframework\boot\spring-boot-autoconfigure\1.5.3.RELEASE\spring-boot-autoconfigure-1.5.3.RELEASE.jar时出错; error in opening zip file [ERROR] 读取E:\Java learn\Maven\apache-maven\org\springframework\boot\spring-boot-autoconfigure\1.5.3.RELEASE\spring-boot-autoconfigure-1.5.3.RELEASE.jar时出错; cannot read zip file [ERROR] /E:/Java learn/All workspacce/dev_springboot/spring-boot-sample/src/main/java/com/example/simple/SpringBootSampleApplication.java:[4,46] 程序包org.springframework.boot.autoconfigure不存在 [ERROR] /E:/Java learn/All workspacce/dev_springboot/spring-boot-sample/src/main/java/com/example/simple/SpringBootSampleApplication.java:[6,2] 找不到符号 [ERROR] 符号: 类 SpringBootApplication [ERROR] -> [Help 1] [ERROR] [ERROR] To see the full stack trace of the errors, re-run Maven with the -e switch. [ERROR] Re-run Maven using the -X switch to enable full debug logging. [ERROR] [ERROR] For more information about the errors and possible solutions, please read the following articles: [ERROR] [Help 1] http://cwiki.apache.org/confluence/display/MAVEN/MojoFailureException 不知道怎么解决,有大神能说下 这个springboot 环境到底怎么搭建吗?
为什么eclisep成功安装sts插件,spring的其他选项都有,唯独没有springboot starter poject这个选项
![图片说明](https://img-ask.csdn.net/upload/201910/03/1570071229_558251.png)![图片说明](https://img-ask.csdn.net/upload/201910/03/1570071261_360349.png)
eclipse Mars2安装sts总是卡在2/15这一步
从Spring官网下载的插件包,版本也是4.5.2的,可是安装总是卡在这儿 ![图片说明](https://img-ask.csdn.net/upload/201703/06/1488763288_906974.png)
eclipse spring.xml文件属性值提示失效
eclipse里面,xml中 类路径提示问题 ,我rinzo+sts插件都安装了,还是没用。(标签是可以提示的,就是写class的时候,这个自动提示不了,已经花了5个小时在搞这个问题,还没解决,求大神带走~) 比如:![图片说明](https://img-ask.csdn.net/upload/201701/19/1484841324_179779.png) 【温馨提示:JavaSE/EE、SSH/SSM、Hybrid APP、JQ/JS/CSS3/H5等编程爱好者加QQ号:28554482,互相学习,共同进步!】
关于Eclipse 无法安装Spring Tools 的问题已经困扰我很长时间
我在学习SSM框架看视频的时候看到老师随手就创建的一个Spring Bean Configuration 文件。 但是我右键点击却没有这个选项,于是了解到要安装Spring Tools这个插件。 首先我去eclipse的Marketplace安装但是一直卡在这个界面 ![图片说明](https://img-ask.csdn.net/upload/201908/15/1565874049_16091.png) 然后我又尝试用安装新软件的功能包括离线和在线然后出现以下情况![图片说明](https://img-ask.csdn.net/upload/201908/15/1565874159_114850.png) 错误信息如下 ![图片说明](https://img-ask.csdn.net/upload/201908/15/1565874228_354000.png) 百度搜说什么是缺少GEF插件,找到链接还是卡在1/15的界面 最后我去Spring官网下载了装有Spring版本的Eclipse (STS 4) 打开首选项看到确实有Spring,但是是残缺的,如下 ![图片说明](https://img-ask.csdn.net/upload/201908/15/1565874608_686504.png) 而正常的是这样 ![图片说明](https://img-ask.csdn.net/upload/201908/15/1565874784_708851.png) 而且改变打开xml文件的选项里没有Spring config Editor 这个问题已经困扰我好长时间,项目也进展不下去,好心人帮帮我吧
SpringBoot中@Autowired注入bean失败:Error creating bean with name“XXXController”?
# 报错信息: ``` org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'authorizeController': Unsatisfied dependency expressed through field 'userMapper'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'userMapper' defined in file [E:\STS-WorkSpace\Forum\target\classes\com\Forum\mapper\UserMapper.class]: Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Property 'sqlSessionFactory' or 'sqlSessionTemplate' are required at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:643) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.annotation.InjectionMetadata.inject(InjectionMetadata.java:116) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor.postProcessProperties(AutowiredAnnotationBeanPostProcessor.java:399) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1422) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:594) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:517) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractBeanFactory.lambda$doGetBean$0(AbstractBeanFactory.java:323) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractBeanFactory$$Lambda$141/1866850137.getObject(Unknown Source) ~[na:na] at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:321) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:202) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:879) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:878) ~[spring-context-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:550) ~[spring-context-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.boot.web.servlet.context.ServletWebServerApplicationContext.refresh(ServletWebServerApplicationContext.java:141) ~[spring-boot-2.2.2.RELEASE.jar:2.2.2.RELEASE] at org.springframework.boot.SpringApplication.refresh(SpringApplication.java:747) [spring-boot-2.2.2.RELEASE.jar:2.2.2.RELEASE] at org.springframework.boot.SpringApplication.refreshContext(SpringApplication.java:397) [spring-boot-2.2.2.RELEASE.jar:2.2.2.RELEASE] at org.springframework.boot.SpringApplication.run(SpringApplication.java:315) [spring-boot-2.2.2.RELEASE.jar:2.2.2.RELEASE] at org.springframework.boot.SpringApplication.run(SpringApplication.java:1226) [spring-boot-2.2.2.RELEASE.jar:2.2.2.RELEASE] at org.springframework.boot.SpringApplication.run(SpringApplication.java:1215) [spring-boot-2.2.2.RELEASE.jar:2.2.2.RELEASE] at com.Forum.ForumApplication.main(ForumApplication.java:19) [classes/:na] Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'userMapper' defined in file [E:\STS-WorkSpace\Forum\target\classes\com\Forum\mapper\UserMapper.class]: Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Property 'sqlSessionFactory' or 'sqlSessionTemplate' are required at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1796) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:595) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:517) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractBeanFactory.lambda$doGetBean$0(AbstractBeanFactory.java:323) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractBeanFactory$$Lambda$141/1866850137.getObject(Unknown Source) ~[na:na] at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:321) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:202) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.config.DependencyDescriptor.resolveCandidate(DependencyDescriptor.java:276) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.DefaultListableBeanFactory.doResolveDependency(DefaultListableBeanFactory.java:1287) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.DefaultListableBeanFactory.resolveDependency(DefaultListableBeanFactory.java:1207) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:640) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] ... 20 common frames omitted Caused by: java.lang.IllegalArgumentException: Property 'sqlSessionFactory' or 'sqlSessionTemplate' are required at org.springframework.util.Assert.notNull(Assert.java:198) ~[spring-core-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.mybatis.spring.support.SqlSessionDaoSupport.checkDaoConfig(SqlSessionDaoSupport.java:123) ~[mybatis-spring-2.0.1.jar:2.0.1] at org.mybatis.spring.mapper.MapperFactoryBean.checkDaoConfig(MapperFactoryBean.java:73) ~[mybatis-spring-2.0.1.jar:2.0.1] at org.springframework.dao.support.DaoSupport.afterPropertiesSet(DaoSupport.java:44) ~[spring-tx-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1855) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1792) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE] ... 31 common frames omitted ``` # Mapper代码: ``` package com.Forum.mapper; import org.apache.ibatis.annotations.Insert; import org.apache.ibatis.annotations.Mapper; import com.Forum.Model.User; @Mapper public interface UserMapper{ @Insert("insert into user (name,account_id,token,gmt_create,gmt_modified) values (#{name},#{accountId}),#{token},#{gmtCreate},#{gmtModified}") public void insert(User user); } ``` # 启动代码: ``` package com.Forum; import org.mybatis.spring.annotation.MapperScan; import org.springframework.boot.SpringApplication; import org.springframework.boot.autoconfigure.SpringBootApplication; import org.springframework.boot.autoconfigure.jdbc.DataSourceAutoConfiguration; import org.springframework.context.annotation.ComponentScan; @SpringBootApplication(exclude = {DataSourceAutoConfiguration.class}) @ComponentScan(basePackages = {"com.Forum.*"}) @MapperScan(basePackages = {"com.Forum.mapper"}) public class ForumApplication { public static void main(String[] args) { SpringApplication.run(ForumApplication.class, args); } } ``` # Controller代码: ```package com.Forum.Controller; import java.util.UUID; import javax.servlet.http.HttpServletRequest; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.beans.factory.annotation.Value; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.GetMapping; import org.springframework.web.bind.annotation.RequestParam; import com.Forum.Dto.AccesstokenDTO; import com.Forum.Dto.GitHubUser; import com.Forum.Model.User; import com.Forum.Provider.GitHubProvider; import com.Forum.mapper.UserMapper; @Controller public class AuthorizeController{ @Autowired private GitHubProvider gitHubProvider; @Value("${github.client.id}") private String clientId; @Value("${github.client.secret}") private String clientSecret; @Value("${github.redirect.uri}") private String redirectUri; @Autowired public UserMapper userMapper; @GetMapping("/callback") public String callback(@RequestParam(name="code") String code, @RequestParam(name="state") String state, HttpServletRequest request ) { AccesstokenDTO accesstokenDTO = new AccesstokenDTO(); accesstokenDTO.setCode(code); accesstokenDTO.setRedirect_uri("redirectUri"); accesstokenDTO.setClient_id(clientId); accesstokenDTO.setClient_secret(clientSecret); accesstokenDTO.setState(state); String accessToken = gitHubProvider.getAccessToken(accesstokenDTO); GitHubUser githubUser = gitHubProvider.getUser(accessToken); if(githubUser != null) { // 登录成功,写cookie和session User user = new User(); user.setToken(UUID.randomUUID().toString()); user.setName(githubUser.getName()); user.setAccountId(String.valueOf(githubUser.getId())); user.setQmtCreate(System.currentTimeMillis()); user.setQmtModified(user.getQmtCreate()); userMapper.insert(user); request.getSession().setAttribute("user", githubUser); return "redirect:/"; // 去掉地址后缀 }else { // 登录失败,重新登录 return "redirect:/"; } } } ```
在eclipse中创建spring starter project出错怎么解决
为什么我已经安好sts插件在eclipse却新建spring starter project还是一直报错
使用Spring Tool Suite (STS)创建application.yml文件创建失败
![图片说明](https://img-ask.csdn.net/upload/201912/04/1575421572_219370.png)
Game Simulator 模拟器的问题
Problem Description “Tractor” is a very popular poker game in China. There are four players in the game. Suppose their names are Alice, Bob, Charles and David, in clockwise order. A judge is needed for this game. The players are divided into two teams, Alice and Charles are in team 1, and the other two are in team 2. The prop they use to play the game are two decks of pokers, including 108 cards in total. A simplified rule of the game is described below. The whole game contains a number of rounds. In each round, one team is called “Declarers” (CT); the other team is called “Defenders” (FT). Each team has a current rank (CR). The goal of the player is to increase his own team's CR as much as possible. A certain round has a Main Suit (Heart - H, Spade - S, Club - C, Diamond - D, or None - no main suit in this round) and its CR. The CR in this round is the CR of the CT, and Main Suit will be given. The Main Suit and CR will be used to determine the order of the cards. Cards ranked 5, 10, King value 5, 10, 10 pts (points) respectively, all other cards value 0 pts. In one round, we only consider the FT's pts. The rules of getting pts for FT will be discussed later. If the FT gets less than 80 pts in one round, they will hold be FT in the next round. This situation is called “make”. Otherwise, they become CT in the next round and the original CT become FT instead. This situation is called “down”. If the FT gets 0 pts, the CR of the current CT will be increased by 3, for example, if the CR of the CT is 9, it will become Queen (12). Otherwise, if the FT gets less than 40 pts, the CR of the CT will be increased by 2. Otherwise, if the FT gets less than 80 pts, the CR of the CT will be increased by 1. Otherwise, if the FT gets not less than 80 + k * 40 pts and less than 120 + k * 40 pts, the CR of the current FT will be increased by k. For example, if the FT gets 255 pts in a round, the CR of the current FT will be increased by 4; and if the FT gets 80 pts, both teams' CR remain unchanged. If a team's CR becomes beyond Ace, this team is considered the WINNER of the whole game. During a round, one of the players in CT is called the dealer. If “make”, the pard (teammate) of the dealer becomes the next round’s dealer. Otherwise (“down”), the player on dealer's right-hand side becomes the dealer of the next round. For example, if the dealer of the current round is Alice and her team (CT) is “down”, the dealer of the next round should be Bob (on Alice's right-hand side). At the start of a round, each of the players except the dealer gets exactly 25 cards; the dealer gets all the remaining 33 cards. After that, the dealer chooses 8 of his cards and gives them to the judge, and these cards are called “hidden cards”. Now each player has exactly 25 cards. A round consists of several tricks. In the first trick, the dealer plays one or more cards (called “lead”), then, in clockwise order, players play the same number of cards as the first player one by one (called “follow”). The winner of the current trick leads cards during the next trick, and so on. If the winner of the current trick is a member of FT, then the FT gets the sum of the cards' pts played in this trick. Now we start to describe how to determine the winner of a trick. After the main suit and the CR of the current round are fixed, we can determine the “trumps” which are cards with main suit or CR (Current Rank), and the Jokers. All other cards are “not-trumps”. We can have an order among all the cards according the following rules: (1) “Trumps” are ordered higher than “not-trumps”. (2) For the trumps, the order are listed below: Red Joker Black Joker card with main suit and CR (if exists) other card with CR other trumps ordered by their ranks(i.e., A, K, Q, J, T, 9, 8, 7, ..., 3, 2) (3) For the “not-trumps”, they are ordered by their ranks. Assume in all the description below, in the current round, the CR of the CT is 7. Suppose the main suit is H, the cards can be arranged in this order (as an example): S2 , C2 , D2 < S3 , C3 , D3 < S4 , C4 , D4 < S5 , C5 , D5 < S6 , C6 , D6 < S8 , C8 , D8 < S9 , C9 , D9 < ST , FT , CT (T - 10) < SJ , CJ , DJ (J - Jack) < SQ , CQ , DQ (Q - Queen) < SK , CK , DK (K - King) < SA , CA , DA (A - Ace) < H2 < H3 < H4 < H5 < H6 < H8 < H9 < HT < HJ < HQ < HK < HA < S7 = C7 = D7 < H7 < BJ (the Black Joker) < RJ (the Red Joker) If “None” during this round, then the pokers can be arranged in this order: H2 , S2 , C2 , D2 < H3 , S3 , C3 , D3 < H4 , S4 , C4 , D4 < H5 , S5 , C5 , D5 < H6 , S6 , C6 , D6 < H8 , S8 , C8 , D8 < H9 , S9 , C9 , D9 < HT , ST , FT , CT < HJ , SJ , CJ , DJ < HQ , SQ , CQ , DQ < HK , SK , CK , DK < HA , SA , CA , DA < H7 = S7 = C7 = D7 < BJ < RJ In these two tables, cards written in italic are “trumps”, and cards written in boldface are “not-trumps”. In each trick, the lead cards (played by the player leading this trick) must be either all “trumps”, or all “not-trumps” with same suit. The possible structures of the cards are listed below (assume the main suit is H and main rank is 7 for the example): Single. A single card, such as D9. Pair. Two same cards, such as D9D9. But D7S7 is not a pair although their orders are the same. Tractor. Two or more consecutive-ordered pairs, satisfying the condition that they are all “trumps”, or all “not-trumps” with same suit, such as SJSJSQSQSKSKSASA, H7H7S7S7HAHA or RJRJBJBJ. But, these are not tractors: S7S7C7C7 (their orders are the same), C7C7C6C6 (they are not consecutive-ordered), DADAD2D2 (Ace is not “one”, so they are not consecutive-ordered), H2H2H4H4, or D2D2D3. Be careful: if “None” in this round, H7H7S7S7HAHA is not a tractor (H7 and S7 are same-ordered because of “None”). Throw. The combination of the structures above, satisfying the condition that they are all “trumps”, or all “not-trumps” with same suit. Each of the Single, Pair or Tractor in a Throw is one of the Throw’s component. In the original tractor game, in some situation, the throw will be rejected. But, to keep the rule simple, we assume in this problem all the throws are accepted. For example, RJRJBJBJH7H7HQHQHJHJH9H9H6H6HAH2 contains six components: two tractors, two pairs and two single cards (RJRJBJBJH7H7-HQHQHJHJ-H9H9-H6H6-HA-H2); CACAC8C8CK contains three components: two pairs and one single card(CACA-C8C8-CK). A throw can be treated as different list of components, for example, H2H2H3H3H4H4H5H5H6H6 can also be treated as H2H2H3H3-H4H4H5H5H6H6, or H2H2-H3H3H4H4H4H5H5-H6H6, and so on. For the lead cards, each time we choose the longest component (choose the one with the highest order to break the tie) to construct a list of components, this list is the structure of the lead cards, also the structure of the trick. So that the structure of the trick is unique. After the first player lead his or her cards, other players follow cards one by one in clockwise order, as mentioned above. An important part of the game is to determine the winner of a trick: If one’s follow cards contain both “trumps” and “not-trumps”, or all “not-trumps” but with different suits, this player can't be winner of this trick. Otherwise, if the lead cards are all “not-trumps” and one’s follow cards contain “not-trumps” with different suit from the lead cards, this follow player can’t be the winner of this trick. Else, if one’s follow cards can't be constructed as the same structure of lead cards, this player can't be the winner of this trick either. Otherwise, if the structure of this trick is not “throw”, the one who played the highest-ordered card wins this trick. If more than one player played the same highest-ordered card, the winner of this trick will be the one who plays the highest-ordered card first. Now let's consider the “throw” situation. We construct the follow cards into the structure of the lead cards, so that the order of the highest-ordered card in all the longest components of the “throw” is as high as possible (this card is called “honor card”). Note that tractor can be treated as several pairs or shorter tractors, and pair can be treated as two single cards. The winner of this trick is the one who plays the highest-ordered “honor card”. Similarly, if more than one player played the same highest-ordered “honor card” the winner of this trick will be the one who plays the highest-ordered “honor card” first. There are many hair-raising rules about lead and follow cards; fortunately, they're not related to this problem, the only thing we care about is: when someone leads a “not-trump” “throw” the only possible way to beat it is to “throw” the same structure of “trumps”. And it’s impossible to beat a leading “trump” “throw”. Special attention on the examples below. In these examples, Alice always leads cards. And assume in all the following examples, the CR is 7, and the main suit is H. There is a special rule about “hidden cards”: if the winner of the last trick of a certain round is a member of FT, then, in addition, the FT gets the sum of the hidden cards' pts, multiplied by 2w (2 to the power of w). When the structure of the final trick is not “throw”, then w is the number of lead cards of the last trick of this round. If the structure is “throw” instead, w is the length of the longest components, in the example RJRJBJBJH7H7HQHQHJHJH6H6HA, the w is 6 because the length of RJRJBJBJH7H7 (the longest components of the “throw”) is 6. To make the problem easier, you are only to write a single-round tractor game simulator. Input Multiple test cases, the number of them T is given in the very first line. For each test case: The first line contains the main suit of this round (H, S, C, D, O; O denotes “None” in this round), the dealer of this round, the CR of team 1, the CR of team 2, separated by single spaces. Each of the rest lines contains 4 strings: the lead cards and the cards played by the second, third and last player. In one string, the cards can be given in any order. Each player will play exactly 25 cards in one round. You may assume the input is always valid. There is a blank line between consecutive test cases, and a blank line also appears between T and the first test case. Output For each test case: The first line contains the case number. The second line contains the pts get by the FT in this round. If a team wins the whole game after this round, output “Winner: Team X”(without quotes, X should be either 1 or 2) in the second line. If no team wins, output the new CR of team 1, the new CR of team 2 after this round, followed by the name of the dealer of the next round, separated by single spaces. See the example for further details. Sample Input 1 O Charles 2 2 S6S6S7S7 SASKSJST STS8S4S4 S3S5SJSQ S9S9 H3D3 S3DT SAD3 DA DQ DK D4 SKS8S5S3 RJC2D2H2 C6C8CJD9 H3CKDTD5 H7H7 H6H4 HJHQ H9H9 DJDJ DKH5 D5D4 D6D6 D8D8 C4C3 HTH5 D9D7 C5C5 C6CT H8HQ C7C4 H8 C7 HA HA H2 RJ BJ CK DA BJ C8 HK S2S2C2 CQCAD2 HTHJHK C9CQCA Sample Output Case #1: 50 3 2 Alice
sts 隐藏dashboard服务
请问sts 的 dashboard如何隐藏不需要的服务 ![图片说明](https://img-ask.csdn.net/upload/201907/25/1563986623_183794.png)
Java学习的正确打开方式
在博主认为,对于入门级学习java的最佳学习方法莫过于视频+博客+书籍+总结,前三者博主将淋漓尽致地挥毫于这篇博客文章中,至于总结在于个人,实际上越到后面你会发现学习的最好方式就是阅读参考官方文档其次就是国内的书籍,博客次之,这又是一个层次了,这里暂时不提后面再谈。博主将为各位入门java保驾护航,各位只管冲鸭!!!上天是公平的,只要不辜负时间,时间自然不会辜负你。 何谓学习?博主所理解的学习,它是一个过程,是一个不断累积、不断沉淀、不断总结、善于传达自己的个人见解以及乐于分享的过程。
程序员必须掌握的核心算法有哪些?
由于我之前一直强调数据结构以及算法学习的重要性,所以就有一些读者经常问我,数据结构与算法应该要学习到哪个程度呢?,说实话,这个问题我不知道要怎么回答你,主要取决于你想学习到哪些程度,不过针对这个问题,我稍微总结一下我学过的算法知识点,以及我觉得值得学习的算法。这些算法与数据结构的学习大多数是零散的,并没有一本把他们全部覆盖的书籍。下面是我觉得值得学习的一些算法以及数据结构,当然,我也会整理一些看过...
大学四年自学走来,这些私藏的实用工具/学习网站我贡献出来了
大学四年,看课本是不可能一直看课本的了,对于学习,特别是自学,善于搜索网上的一些资源来辅助,还是非常有必要的,下面我就把这几年私藏的各种资源,网站贡献出来给你们。主要有:电子书搜索、实用工具、在线视频学习网站、非视频学习网站、软件下载、面试/求职必备网站。 注意:文中提到的所有资源,文末我都给你整理好了,你们只管拿去,如果觉得不错,转发、分享就是最大的支持了。 一、电子书搜索 对于大部分程序员...
linux系列之常用运维命令整理笔录
本博客记录工作中需要的linux运维命令,大学时候开始接触linux,会一些基本操作,可是都没有整理起来,加上是做开发,不做运维,有些命令忘记了,所以现在整理成博客,当然vi,文件操作等就不介绍了,慢慢积累一些其它拓展的命令,博客不定时更新 free -m 其中:m表示兆,也可以用g,注意都要小写 Men:表示物理内存统计 total:表示物理内存总数(total=used+free) use...
比特币原理详解
一、什么是比特币 比特币是一种电子货币,是一种基于密码学的货币,在2008年11月1日由中本聪发表比特币白皮书,文中提出了一种去中心化的电子记账系统,我们平时的电子现金是银行来记账,因为银行的背后是国家信用。去中心化电子记账系统是参与者共同记账。比特币可以防止主权危机、信用风险。其好处不多做赘述,这一层面介绍的文章很多,本文主要从更深层的技术原理角度进行介绍。 二、问题引入 假设现有4个人...
程序员接私活怎样防止做完了不给钱?
首先跟大家说明一点,我们做 IT 类的外包开发,是非标品开发,所以很有可能在开发过程中会有这样那样的需求修改,而这种需求修改很容易造成扯皮,进而影响到费用支付,甚至出现做完了项目收不到钱的情况。 那么,怎么保证自己的薪酬安全呢? 我们在开工前,一定要做好一些证据方面的准备(也就是“讨薪”的理论依据),这其中最重要的就是需求文档和验收标准。一定要让需求方提供这两个文档资料作为开发的基础。之后开发...
网页实现一个简单的音乐播放器(大佬别看。(⊙﹏⊙))
今天闲着无事,就想写点东西。然后听了下歌,就打算写个播放器。 于是乎用h5 audio的加上js简单的播放器完工了。 演示地点演示 html代码如下` music 这个年纪 七月的风 音乐 ` 然后就是css`*{ margin: 0; padding: 0; text-decoration: none; list-...
Python十大装B语法
Python 是一种代表简单思想的语言,其语法相对简单,很容易上手。不过,如果就此小视 Python 语法的精妙和深邃,那就大错特错了。本文精心筛选了最能展现 Python 语法之精妙的十个知识点,并附上详细的实例代码。如能在实战中融会贯通、灵活使用,必将使代码更为精炼、高效,同时也会极大提升代码B格,使之看上去更老练,读起来更优雅。
数据库优化 - SQL优化
以实际SQL入手,带你一步一步走上SQL优化之路!
2019年11月中国大陆编程语言排行榜
2019年11月2日,我统计了某招聘网站,获得有效程序员招聘数据9万条。针对招聘信息,提取编程语言关键字,并统计如下: 编程语言比例 rank pl_ percentage 1 java 33.62% 2 cpp 16.42% 3 c_sharp 12.82% 4 javascript 12.31% 5 python 7.93% 6 go 7.25% 7 p...
通俗易懂地给女朋友讲:线程池的内部原理
餐盘在灯光的照耀下格外晶莹洁白,女朋友拿起红酒杯轻轻地抿了一小口,对我说:“经常听你说线程池,到底线程池到底是个什么原理?”
《奇巧淫技》系列-python!!每天早上八点自动发送天气预报邮件到QQ邮箱
将代码部署服务器,每日早上定时获取到天气数据,并发送到邮箱。 也可以说是一个小型人工智障。 知识可以运用在不同地方,不一定非是天气预报。
经典算法(5)杨辉三角
杨辉三角 是经典算法,这篇博客对它的算法思想进行了讲解,并有完整的代码实现。
英特尔不为人知的 B 面
从 PC 时代至今,众人只知在 CPU、GPU、XPU、制程、工艺等战场中,英特尔在与同行硬件芯片制造商们的竞争中杀出重围,且在不断的成长进化中,成为全球知名的半导体公司。殊不知,在「刚硬」的背后,英特尔「柔性」的软件早已经做到了全方位的支持与支撑,并持续发挥独特的生态价值,推动产业合作共赢。 而对于这一不知人知的 B 面,很多人将其称之为英特尔隐形的翅膀,虽低调,但是影响力却不容小觑。 那么,在...
腾讯算法面试题:64匹马8个跑道需要多少轮才能选出最快的四匹?
昨天,有网友私信我,说去阿里面试,彻底的被打击到了。问了为什么网上大量使用ThreadLocal的源码都会加上private static?他被难住了,因为他从来都没有考虑过这个问题。无独有偶,今天笔者又发现有网友吐槽了一道腾讯的面试题,我们一起来看看。 腾讯算法面试题:64匹马8个跑道需要多少轮才能选出最快的四匹? 在互联网职场论坛,一名程序员发帖求助到。二面腾讯,其中一个算法题:64匹...
面试官:你连RESTful都不知道我怎么敢要你?
干货,2019 RESTful最贱实践
刷了几千道算法题,这些我私藏的刷题网站都在这里了!
遥想当年,机缘巧合入了 ACM 的坑,周边巨擘林立,从此过上了"天天被虐似死狗"的生活… 然而我是谁,我可是死狗中的战斗鸡,智力不够那刷题来凑,开始了夜以继日哼哧哼哧刷题的日子,从此"读题与提交齐飞, AC 与 WA 一色 ",我惊喜的发现被题虐既刺激又有快感,那一刻我泪流满面。这么好的事儿作为一个正直的人绝不能自己独享,经过激烈的颅内斗争,我决定把我私藏的十几个 T 的,阿不,十几个刷题网...
为啥国人偏爱Mybatis,而老外喜欢Hibernate/JPA呢?
关于SQL和ORM的争论,永远都不会终止,我也一直在思考这个问题。昨天又跟群里的小伙伴进行了一番讨论,感触还是有一些,于是就有了今天这篇文。 声明:本文不会下关于Mybatis和JPA两个持久层框架哪个更好这样的结论。只是摆事实,讲道理,所以,请各位看官勿喷。 一、事件起因 关于Mybatis和JPA孰优孰劣的问题,争论已经很多年了。一直也没有结论,毕竟每个人的喜好和习惯是大不相同的。我也看...
白话阿里巴巴Java开发手册高级篇
不久前,阿里巴巴发布了《阿里巴巴Java开发手册》,总结了阿里巴巴内部实际项目开发过程中开发人员应该遵守的研发流程规范,这些流程规范在一定程度上能够保证最终的项目交付质量,通过在时间中总结模式,并推广给广大开发人员,来避免研发人员在实践中容易犯的错误,确保最终在大规模协作的项目中达成既定目标。 无独有偶,笔者去年在公司里负责升级和制定研发流程、设计模板、设计标准、代码标准等规范,并在实际工作中进行...
SQL-小白最佳入门sql查询一
不要偷偷的查询我的个人资料,即使你再喜欢我,也不要这样,真的不好;
项目中的if else太多了,该怎么重构?
介绍 最近跟着公司的大佬开发了一款IM系统,类似QQ和微信哈,就是聊天软件。我们有一部分业务逻辑是这样的 if (msgType = "文本") { // dosomething } else if(msgType = "图片") { // doshomething } else if(msgType = "视频") { // doshomething } else { // doshom...
Nginx 原理和架构
Nginx 是一个免费的,开源的,高性能的 HTTP 服务器和反向代理,以及 IMAP / POP3 代理服务器。Nginx 以其高性能,稳定性,丰富的功能,简单的配置和低资源消耗而闻名。 Nginx 的整体架构 Nginx 里有一个 master 进程和多个 worker 进程。master 进程并不处理网络请求,主要负责调度工作进程:加载配置、启动工作进程及非停升级。worker 进程负责处...
【图解经典算法题】如何用一行代码解决约瑟夫环问题
约瑟夫环问题算是很经典的题了,估计大家都听说过,然后我就在一次笔试中遇到了,下面我就用 3 种方法来详细讲解一下这道题,最后一种方法学了之后保证让你可以让你装逼。 问题描述:编号为 1-N 的 N 个士兵围坐在一起形成一个圆圈,从编号为 1 的士兵开始依次报数(1,2,3…这样依次报),数到 m 的 士兵会被杀死出列,之后的士兵再从 1 开始报数。直到最后剩下一士兵,求这个士兵的编号。 1、方...
吐血推荐珍藏的Visual Studio Code插件
作为一名Java工程师,由于工作需要,最近一个月一直在写NodeJS,这种经历可以说是一部辛酸史了。好在有神器Visual Studio Code陪伴,让我的这段经历没有更加困难。眼看这段经历要告一段落了,今天就来给大家分享一下我常用的一些VSC的插件。 VSC的插件安装方法很简单,只需要点击左侧最下方的插件栏选项,然后就可以搜索你想要的插件了。 下面我们进入正题 Material Theme ...
如何防止抄袭PCB电路板
目录 1、抄板是什么 2、抄板是否属于侵权 3、如何防止抄板 1、抄板是什么 抄板也叫克隆或仿制,是对设计出来的PCB板进行反向技术研究;目前全新的定义:从狭义上来说,抄板仅指对电子产品电路板PCB文件的提取还原和利用文件进行电路板克隆的过程;从广义上来说,抄板不仅包括对电路板文件提取、电路板克隆、电路板仿制等技术过程,而且包括对电路板文件进行修改(即改板)、对电子产品外形模具进行三维...
“狗屁不通文章生成器”登顶GitHub热榜,分分钟写出万字形式主义大作
一、垃圾文字生成器介绍 最近在浏览GitHub的时候,发现了这样一个骨骼清奇的雷人项目,而且热度还特别高。 项目中文名:狗屁不通文章生成器 项目英文名:BullshitGenerator 根据作者的介绍,他是偶尔需要一些中文文字用于GUI开发时测试文本渲染,因此开发了这个废话生成器。但由于生成的废话实在是太过富于哲理,所以最近已经被小伙伴们给玩坏了。 他的文风可能是这样的: 你发现,...
程序员:我终于知道post和get的区别
是一个老生常谈的话题,然而随着不断的学习,对于以前的认识有很多误区,所以还是需要不断地总结的,学而时习之,不亦说乎
《程序人生》系列-这个程序员只用了20行代码就拿了冠军
你知道的越多,你不知道的越多 点赞再看,养成习惯GitHub上已经开源https://github.com/JavaFamily,有一线大厂面试点脑图,欢迎Star和完善 前言 这一期不算《吊打面试官》系列的,所有没前言我直接开始。 絮叨 本来应该是没有这期的,看过我上期的小伙伴应该是知道的嘛,双十一比较忙嘛,要值班又要去帮忙拍摄年会的视频素材,还得搞个程序员一天的Vlog,还要写BU...
加快推动区块链技术和产业创新发展,2019可信区块链峰会在京召开
11月8日,由中国信息通信研究院、中国通信标准化协会、中国互联网协会、可信区块链推进计划联合主办,科技行者协办的2019可信区块链峰会将在北京悠唐皇冠假日酒店开幕。   区块链技术被认为是继蒸汽机、电力、互联网之后,下一代颠覆性的核心技术。如果说蒸汽机释放了人类的生产力,电力解决了人类基本的生活需求,互联网彻底改变了信息传递的方式,区块链作为构造信任的技术有重要的价值。   1...
Python 植物大战僵尸代码实现(2):植物卡片选择和种植
这篇文章要介绍的是: - 上方植物卡片栏的实现。 - 点击植物卡片,鼠标切换为植物图片。 - 鼠标移动时,判断当前在哪个方格中,并显示半透明的植物作为提示。
相关热词 c#委托 逆变与协变 c#新建一个项目 c#获取dll文件路径 c#子窗体调用主窗体事件 c# 拷贝目录 c# 调用cef 网页填表c#源代码 c#部署端口监听项目、 c#接口中的属性使用方法 c# 昨天
立即提问